how long would free fall last with no problems just a simple fall for 60 miles up in an elevator shaft?

Question

just how much time just the freefall nothing else

Answer 1

You have to integrate. At 60 miles above the surface of the earth the acceleration due to gravity is not 9.8m/s^2. Use the formula for gravitational acceleration and plug it into the differential form of the distance formula and integrate with the bounds of Re+60mi to Re, where Re is the radius of the earth.

We could make it really complicated and factor in air resistance. Or better yet. if you were wearing extremely baggy clothes that puffed up to nearly the size of the shaft you might fall gracefully like a dandelion in the wind.

Or you can just plug into the regular distance formula and neglect changes in gravity. I'm sure it'll be close enough for whatever you're doing =P

Answer 2

throughout the time of free-fall, the human body falls at about one hundred and fifty miles per hour. it somewhat is terminal velocity, even as the pull of gravity and air friction equivalent one yet another. An elevator in a shaft, starting up at fifty 9 miles altitude (the sting of area) may initially fall speedier than that. because the air were given denser, the resistance it generated may sluggish the elevator down. How a lot the elevator may decelerate relies upon on how a lot room there is between the elevator and the perimeters of the elevator shaft. The air lower than the elevator may compress a twin of a spring because the elevator fell, till the rigidity relief from the air being pressured previous the elevator and the rigidity created by skill of the falling body equalized. with out specifics, you won't be able to compute what this rigidity and the consequent terminal velocity of the elevator may be.

Answer 3

H = 1/2 a t^2 (free fall in vacuum)
60*5280 = 1/2 * 32 t^2
T = 140 seconds.

however the air resistance will cause you to reach a terminal velocity and slow you down thus increasing the time of the fall.

Answer 4

Assuimg you're talking about a person free-falling in air, remember that air resistance will come in to play and keep them at a terminal speed. A person's terminal velocity in free fall is about 120 mph (about 54 m/s). So, just divide the distance traveled by the terminal velocity and you'll get the time of the fall.

Answer 5

Besides air resistance and the attitude of the body, your question omits the position of the sun and the moon, and the ambient temperature of the air at an infinite number of intervals along the varying density in a column 60 miles high.
Do you have a particular body in mind?

Answer 6

Neglecting air resistance and other forms of friction, a body in [what we will assume is] a uniform gravitational field will accelerate downward toward the ground at 9.81 m/s^2.

60 miles is 96,560.64 meters.

Using this equation,
d = 1/2at^2
where a is the uniform gravitational acceleration, d is the distance the object will fall, and t is the time it takes to fall (no initial up/down velocity).
rearranging this equation gives us,
t = sqrt (2d / a)
t = sqrt (193,121.28 / 9.81)
t = sqrt (19,686.1651)
t is about 140.3 seconds with a final downward velocity as the object hits the ground of 1376.3 m/s (over 3000 miles per hour).

Answer 7

Between 2-3 seconds. Assuming negligible wind resistance and no obstructions, freefall would occur at 22mph/s.

Answer 8

a free fall in an elevator shaft is a big problem in itself I would think

Answer 9

First second 9.8 meters, second second 19.6, third second -29.4....keep adding till you get 60 miles....that is 60X1600 meters.