English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

a. sin x/n=6
b. IX=6
c. 2=1
have fun in solving these problems..

2006-07-11 04:02:38 · 12 answers · asked by Anonymous in Science & Mathematics Mathematics

12 answers

a) sin x/n=si(n*1/n)x=si(1)x=six=6
(by t rex boy)

b) from a) SIX=6
Here S seems to indicate "turn upside down IX "
and in roman numerals IX=9
so we get 6

c) TWO = TW*0 = 0
ONE = 0*NE = 0
so TWO = ONE
i.e. 2=1

2006-07-11 20:59:15 · answer #1 · answered by 11:11 3 · 2 0

First I solve the third one.
Let x = y = 1

taking x = y,

multiplying with x, x^2 = xy

substracting y^2 on both sides, x^2 - y^2 = xy - y^2

(x + y) (x - y) = y (x - y)

gives x + y = y

substituting the values of x and y in the above equations gives the result 2 = 1.

{ This is wrong because only non zero terms should be cancelled on the either sides. This is a rule. That's why we got the result 2 = 1 which is false }

Comming to the second one. This is so simple.

Just keep the letter S before IX then you will get the result, SIX = 6.

The first one is as follows.

sin x/n
taking n inside and x out side, si(n/n)x
both the n's will be cancelled, si(1)x
as anything multiplied with 1 gives the same thing so it is six

Theoritically all the above results are false.
Normally sin x range is [-1,1] so sin (x/n) cannot be six.

Hope you like this.

2006-07-11 11:15:51 · answer #2 · answered by Sherlock Holmes 6 · 0 0

First I solve the third one.
Let x = y = 1

taking x = y,

multiplying with x, x^2 = xy

substracting y^2 on both sides, x^2 - y^2 = xy - y^2

(x + y) (x - y) = y (x - y)

gives x + y = y

substituting the values of x and y in the above equations gives the result 2 = 1.

{ This is wrong because only non zero terms should be cancelled on the either sides. This is a rule. That's why we got the result 2 = 1 which is false }

Comming to the second one. This is so simple.

Just keep the letter S before IX then you will get the result, SIX = 6.

The first one is as follows.

sin x/n
taking n inside and x out side, si(n/n)x
both the n's will be cancelled, si(1)x
as anything multiplied with 1 gives the same thing so it is six

Theoritically all the above results are false.
Normally sin x range is [-1,1] so sin (x/n) cannot be six.

2006-07-11 12:04:23 · answer #3 · answered by sayan 2 · 0 0

a. false. Sine has a range [-1,1] without amplitude modulation
b. l*X=6. Need more information on what I or X is to determine the value of the other.
c. false

2006-07-11 11:12:55 · answer #4 · answered by bequalming 5 · 0 0

what is this, a line graph problem? because 2 cannot equal 1.

2006-07-11 11:05:55 · answer #5 · answered by jayztttight 4 · 0 0

assume a = x

a+a = a+x
2a = a+x
2a-2x = a+x-2x
2(a-x) = a+x-2x
2(a-x) = a-x
2 = 1

2006-07-11 11:50:27 · answer #6 · answered by _Bogie_ 4 · 0 0

a.
sin x/n
=si(n/n)x
=si(1)x
=six
=6
therefore, sin x/n = 6

2006-07-11 11:08:39 · answer #7 · answered by mom fucker 3 · 0 0

to the guy above me, a cannot equal x because you are dividing by zero, this question is retarded.

2006-07-11 11:56:28 · answer #8 · answered by Eric D 3 · 0 0

answers to a, b and c are false

2006-07-11 11:09:15 · answer #9 · answered by sleepyxzzzz 3 · 0 0

a. some crap i learned in school.
b. what.
c. your crazy?

2006-07-11 11:07:20 · answer #10 · answered by Anonymous · 0 0

fedest.com, questions and answers