a) sin x/n=si(n*1/n)x=si(1)x=six=6
(by t rex boy)
b) from a) SIX=6
Here S seems to indicate "turn upside down IX "
and in roman numerals IX=9
so we get 6
c) TWO = TW*0 = 0
ONE = 0*NE = 0
so TWO = ONE
i.e. 2=1
2006-07-11 20:59:15
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answer #1
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answered by 11:11 3
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First I solve the third one.
Let x = y = 1
taking x = y,
multiplying with x, x^2 = xy
substracting y^2 on both sides, x^2 - y^2 = xy - y^2
(x + y) (x - y) = y (x - y)
gives x + y = y
substituting the values of x and y in the above equations gives the result 2 = 1.
{ This is wrong because only non zero terms should be cancelled on the either sides. This is a rule. That's why we got the result 2 = 1 which is false }
Comming to the second one. This is so simple.
Just keep the letter S before IX then you will get the result, SIX = 6.
The first one is as follows.
sin x/n
taking n inside and x out side, si(n/n)x
both the n's will be cancelled, si(1)x
as anything multiplied with 1 gives the same thing so it is six
Theoritically all the above results are false.
Normally sin x range is [-1,1] so sin (x/n) cannot be six.
Hope you like this.
2006-07-11 11:15:51
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answer #2
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answered by Sherlock Holmes 6
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First I solve the third one.
Let x = y = 1
taking x = y,
multiplying with x, x^2 = xy
substracting y^2 on both sides, x^2 - y^2 = xy - y^2
(x + y) (x - y) = y (x - y)
gives x + y = y
substituting the values of x and y in the above equations gives the result 2 = 1.
{ This is wrong because only non zero terms should be cancelled on the either sides. This is a rule. That's why we got the result 2 = 1 which is false }
Comming to the second one. This is so simple.
Just keep the letter S before IX then you will get the result, SIX = 6.
The first one is as follows.
sin x/n
taking n inside and x out side, si(n/n)x
both the n's will be cancelled, si(1)x
as anything multiplied with 1 gives the same thing so it is six
Theoritically all the above results are false.
Normally sin x range is [-1,1] so sin (x/n) cannot be six.
2006-07-11 12:04:23
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answer #3
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answered by sayan 2
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a. false. Sine has a range [-1,1] without amplitude modulation
b. l*X=6. Need more information on what I or X is to determine the value of the other.
c. false
2006-07-11 11:12:55
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answer #4
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answered by bequalming 5
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what is this, a line graph problem? because 2 cannot equal 1.
2006-07-11 11:05:55
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answer #5
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answered by jayztttight 4
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assume a = x
a+a = a+x
2a = a+x
2a-2x = a+x-2x
2(a-x) = a+x-2x
2(a-x) = a-x
2 = 1
2006-07-11 11:50:27
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answer #6
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answered by _Bogie_ 4
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a.
sin x/n
=si(n/n)x
=si(1)x
=six
=6
therefore, sin x/n = 6
2006-07-11 11:08:39
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answer #7
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answered by mom fucker 3
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to the guy above me, a cannot equal x because you are dividing by zero, this question is retarded.
2006-07-11 11:56:28
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answer #8
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answered by Eric D 3
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answers to a, b and c are false
2006-07-11 11:09:15
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answer #9
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answered by sleepyxzzzz 3
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a. some crap i learned in school.
b. what.
c. your crazy?
2006-07-11 11:07:20
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answer #10
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answered by Anonymous
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