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Can a vector in any case can have a component perpendicular to it?

2006-07-11 03:28:28 · 5 answers · asked by Anonymous in Science & Mathematics Physics

If yes, then can a force have a component perpendicular to it?

2006-07-11 03:39:44 · update #1

5 answers

A Vector has 3 components in 3-D.

A component of vector is a scalar and it has the direction along the i,j or k axis. As scalar cannot have components, a vector component cannot be resolved into more components.

2006-07-11 05:32:19 · answer #1 · answered by Sherlock Holmes 6 · 0 1

yes a component of a vector can also have component because the component is itself a vector. yes a force can have one of its component perpendicular to it . you must be guessing how it would be possible because let us not forget the other component of the force . let us consider a force is acting towards east . let us take the component 1 in south direction. then the component 2 is in the direction between north and east with any numerical value which again depends on the component 1.
now if you find the component of component 2 in the east direction withe same value as the first force then the other component of the component 2 will be in north direction and its value will be equal to the component 1 and hence both get cancelled . leaving you with the same force like the first force.

2006-07-11 14:26:37 · answer #2 · answered by tihor ydder 1 · 0 0

Yes.
For example the projection of a 3D vector on a plane is a 2D vector so this 3D vector is made up of an (x,y) vector component and a z vector component (2 components). The 2D vector can be further resolved into an x vector component and a y vector component.

2006-07-11 10:32:50 · answer #3 · answered by mashkas 3 · 0 0

sure...every vector in a 2-d or 3-d space can be represented as the sum of different vectors...therefore it can be resolved into more components

2006-07-11 10:32:47 · answer #4 · answered by teja_girl 2 · 0 0

yes, since it is a vector, it wil allow other components to be formed, allowing easier calculations

2006-07-11 10:35:54 · answer #5 · answered by noob 1 · 0 0

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