how do we derive at 273kelvin?

Answer 1

When we set zero Celcius, we had no idea where absolute zero was, or even the existence of absolute zero.

Zero celcius is not exactly 273K, it's closer to 273.15K, but that is still rounding.

Therefore, the values of K to C are just an accident. C was based on water, and K was based on absolute zero, and when K was set they decided to use the same increment-size as C.

Answer 2

Vt=Vo(1+alpha t) where Vt is the volume at t deg Celsius,Vo is the vol at zero deg Celsius and alpha is the coefficient of voluminar expansion for every degree Celsius which is 1/273
so Vt=Vo(1+1/273t)
for finding out the temp at which the volume of the gas is zero
equating 1+1/273=0 we get t=-273 deg Celsius.so -273 deg Celsius is the temp at which the volume of the gas is zero.taking this as o K the absolute scale came into vogue.
the same expression can be derived from
Pt=Po(1+alpha t)
both these derivations are based upon the Charlie's law

Answer 3

Celsius is based on tempurature water freezes and boils. Set at 0 and 100 so that they are round numbers. Kelvin grade (difference between degrees) is based on Celsius. In other words, Kelvin was calculated using Celsius as base. Abolute zero was set at 0 Kelvin. Using "size" of degrees, it naturally occured that 0 Celsius = 273 Kelvin. Is this clear?

Answer 4

The ideal gas law. If you look at how much a gas shrinks when the temperature goes down, it will shrink to nothing at 0 kelvins. Obviously that doesn't really apply to any real gasses, but the "law" is still useful.

Answer 5

I dont understand what you mean, though that is the freezing point of water.

Answer 6

This is not such a good question. Add more details.

Answer 7

Pardon... please rephrase your question...

273 K = 0°C
273 K = 32°F