2006-07-11 02:49:07 · 7 answers · asked by Libra Princess 3 in Science & Mathematics ➔ Mathematics
Another way of looking at it:
perimeter of all the hexagons added together - the sides that
touch
= 50 (6*1) - 49*2 = 300-98 = 202 dm
2006-07-11 07:18:05 · answer #1 · answered by raz 5 · 0⤊ 0⤋
202dm.
A hexagon has 6 sides. If a hexagon is put side to side it will have 4 sides that are not connected But the ends of each will have 5 sides since it is the end.
4*48=192
2*5=10
192+10=202
2006-07-11 10:06:57 · answer #2 · answered by Eric X 5 · 0⤊ 0⤋
As, 50 hexagons are connected side by side, and each side is 1dm, the perimeter of the first hexagon is 6dm, while the perimeters of each hexagons after the first is 5dm. So, the total perimeter of all the hexagons is as follows:
6dm +(49*5)dm = 6dm+245dm
= 251dm.
2006-07-11 11:17:36 · answer #3 · answered by surgb6 1 · 0⤊ 0⤋
(48*4*1+2*5*1) dm
(160+32+10) dm
202 dm
2006-07-11 09:53:25 · answer #4 · answered by bequalming 5 · 0⤊ 0⤋
202 dm
2006-07-11 10:37:07 · answer #5 · answered by Walt C 3 · 0⤊ 0⤋
202 Decca meaters
2006-07-11 09:58:07 · answer #6 · answered by radhi 2 · 0⤊ 0⤋
i agree with 202!!!!!!! i too calc it............
2006-07-11 10:00:01 · answer #7 · answered by nijas 2 · 0⤊ 0⤋