In an isosceles right triangle, one of the congruent sides has a measure 7 cm.?

Question

In an isosceles right triangle, one of the congruent sides has a measure 7 cm. Find the measure of the hypotenuse.

Answer 1

we know two things from this problem that aren't really given.

1: Since it's isosceles, we know that both it's legs are the same length.
2: Since it's a right triangle, we know the square of it's hypoteneuse is equal to the sum of the square of it's legs.

So, we know:
A(7)^2 + B(7)^2 = C^2
49 + 49 = C^2
98 = C^2
sqrt(98)=C
Sqrt(49)*Sqrt(2)=C
7Sqrt(2)=C

Answer 2

According to your information, the perimeter is the sum of length of all sides. So, the perimeter is Perimeter=(2x + 9) + (2x + 9) + (3x) Since the perimeter is known to be 60 inches, 60 = (2x + 9) + (2x + 9) + (3x) or, 60 = 2(2x + 9) + 3x = 4x + 18 + 3x = 7x + 18 60 - 18 = 7x 42 = 7x 42/7=x x=6 Therefore, x = 6

Answer 3

Impossible without knowing the angle at the apex. All that can be said is that it's between 0.000000000000000.....001 cm and 13.9999999999999... cm

Answer 4

Don't you think you would be better trying to work through some of these problems yourself rather than just asking for the answers? You'll never learn that way.

Answer 5

I already have a GCSE in Maths, 2 A-levels in Maths and 2 Engineering degrees. I have done enough Maths homework in my time, it is now time for you to do your own homework!

Answer 6

the square root of 98

Answer 7

a^2+b^2=c^2

so if this is correct
49+49=98

square root of 98

Answer 8

Hypotenuse is also 7cm

Answer 9

How about, um.....you try doing your own homework, dude

Answer 10

is that all you know is about triangles