2006-07-11 02:40:37 · 6 answers · asked by Anonymous in Education & Reference ➔ Homework Help
The altitude of an equilateral triangle is equal to sqrt(3) times half the length of a leg.
So, the length of a leg is 2(7/sqrt(3)) = 14sqrt(3)/3
2006-07-11 02:44:51 · answer #1 · answered by mathsmart 4 · 2⤊ 1⤋
Draw yourself a picture. Call each side x.
Divide the equilateral triangle into two triangles, using the altitutde.
For one the two triangles, which are right triangles, the sides are 7, x/2, and x.
By Pythagoreagn,
(7)^2 + (x/2)^2 = x^2.
Can you finish it from here?
2006-07-11 09:46:49 · answer #2 · answered by fcas80 7 · 0⤊ 0⤋
You'll form a 30-60-90 triangle when you drop the altitude.
In such a triangle, they hypotenuse is the side of your original equilateral triangle. Cos 60= altitude/side. Side=7cm/cos60=8.08 cm
2006-07-11 09:47:14 · answer #3 · answered by Iridium190 5 · 0⤊ 0⤋
Follow: A squared +B squared = C square
C= 7 cm.
B= 1/2 A
Therefore: A squared + 1/2 A Squared = C Squared
A squared + 1/2 A Squared = 49
The rest is up to you.
2006-07-11 09:50:29 · answer #4 · answered by profdave99 3 · 0⤊ 0⤋
for a equilateral triangle
altitude=sqrt(3/4)*side;
so u cn find the side using this relation.
2006-07-11 09:45:11 · answer #5 · answered by ashish k 1 · 0⤊ 0⤋
3.5 square roots of 3 cm
2006-07-11 09:44:09 · answer #6 · answered by Anonymous · 0⤊ 0⤋