derivation of kelvin scale of temprature?

Question

how to derive 273 kelvin

Answer 1

the kelvin scales has the same graduations as centigrade but it starts at absolute zero which is approx -273 deg C

so, subtract 273 fromthe temperature in K to get it in C

Answer 2

Vt=Vo(1+alpha t) where Vt is the volume at t deg Celsius,Vo is the vol at zero deg Celsius and alpha is the coefficient of voluminar expansion for every degree Celsius which is 1/273
so Vt=Vo(1+1/273t)
for finding out the temp at which the volume of the gas is zero
equating 1+1/273=0 we get t=-273 deg Celsius.so -273 deg Celsius is the temp at which the volume of the gas is zero.taking this as o K the absolute scale came into vogue.
the same expression can be derived from
Pt=Po(1+alpha t)
both these derivations are based upon the Charlie's law

Answer 3

The Kelvin scale is based on "absolute 0", a temperature at which, in theory all molecular motion ceases.
The conversion scale is (Temp in Centigrade)+273.

Answer 4

On the kelvin scale 273 is added to the degree celsius temperature. There water will boil at 373 Kelvin (100oC + 273)

Answer 5

Kelvin is a measurement of temperature that shares the same divisions as Centigrade but it begins at Absolute Zero, the point at which everything stops down to subatomic levels

Answer 6

hhmmm..

probably..there will be no derivation.. USING FORMULA OR concept of ALGEBRA

it is said that the absolute zero is the lowest possible temperature ..

and that lowest possible is -273C


so..

K= C +273

Answer 7

ºC+273=K

ºC=273-273

273K = 0­°C

Answer 8

nice hood.