I want to know about current, resistance and voltage.?

Question

i am goin to make a circuit demonstrating electric wind. in the experiment, i have to connect a wire to a power source. the other end of the wire is allowed to discharge slowly into the air. If my current is abt 0.5 A, since my resistance is very high, what voltage will i get. What do i do to increase it?

hello. if u wanna know what i'm trying to make, go to http://membres.lycos.fr/plasmapropulsion/Historical_%26_Basic/Electric_Wind.htm
Tre, very good, u found de very site i was refferring to. Yohan, V = IR not I/R
Jalaj, i haven't been fooled by anyone, the wire is discharging at one end, thats why the current is small compared to the high expected voltage(2000 volts)
P. B., i know abt electricity; voltage, current and resistance and the water analogy, what i wanted to know was, since I = V/R, and my resistance is very high, logically, i should have to have a very high voltage to get a considerable current. Is that right?

Answer 1

You are not giving enough information to help you out.

Answer 2

You obviously have no idea what you are doing or saying. Sorry. Electricity is just like water. With electricity you have Voltage measured in volts, current measured in amps, and resistance measured in ohms. With water, you have Pressure measured in pounds per square inch, flow measured in gallons per minute, and the last item would be pipe size measured in inches. Voltage is akin to Pressure in that it is what pushes the electrons down the wire. More pressure or voltage= more flow. What would restrict the flow would be a resistor for electricity, or small pipe for water. when measured across the small pipe, or resistor, you will measure a voltage drop or pressure drop. The drop in pressure or voltage is related to minimized flow. Want more flow? Raise the voltage, or reduce the resistance. As for the formula, Voltage =Current X Resistance, or, stated another way, Current= Voltage divided by Resistance, so plug in your values, and using simple math you should be able to determine your values required to achieve a desired outcome. You have specified the desired current flow, now you need to determine the resistance which exists in order to complete the equation and solve the problem. Remember, if you can decrease the resistance by say humidifying the air, the total voltage required to achieve the same current flow will be reduced. Research "Ohm's Law" for more info on the above. Good luck, and be careful!!!!! I do not recommend playing with high voltage especially when combined with a moist environment.

Answer 3

i think either u have been fooled by ur teachers or u r trying to fool all the ppl out here coz a current will never flow in an open circuit
but in both the cases the ppl hu have answered u r ediots
anyways if u want to calculate the voltage then the formula is-
V=IxR
if u want to increase the voltage then u can use a rheostat which is an instrument to increase the curren flowing.
since current is directly propotional to voltage therefore if current is increased then voltage will also increase.
but for all this u'll have to complete the circuit first

Answer 4

imagine of a water hose. The water flowing contained in the hose is the present. there is water stress pushing the present by potential of the hose. You get swifter water bypass with a large hose than you get with a small hose. The hose promises resistance. Pinching the hose will develop the resistance, which makes the waterflow smaller. electrical energy is an same way. contemporary is the charged debris flowing (electrons in a twine) stress is the voltage pushing the charged debris by potential of the twine. You get extra contemporary go by potential of a large twine than slightly twine. The battery cables on your automobile are large wires. they could carry 1000's of amperes. The twine connecting your computer to the wall socket is a smaller twine. it may in ordinary words carry about 10 to fifteen amperes; in case you're attempting to push one hundred amperes by potential of it then it ought to get warm, melt the insulation, or maybe probably melt the copper twine interior. The battery cable on your automobile has a low resistance, the twine on your computer has a larger resistance. you ought to apply tremendous-twine cables to bounce-commence a automobile hence. electric powered calculations are surprisingly ordinary. you could degree the voltage with a voltmeter. you purely placed the probes in the course of the device you want to degree. you could degree contemporary with an ammeter. you're making the ammeter part of the circuit, a twin of a water meter is put in contained in the water line. You degree voltage, you degree contemporary, and also you'll calculate the resistance by employing Voltage divided by employing contemporary = resistance. This works for battery operated kit and it fairly works for gadgets you plug into the wall sockets, yet because the voltage in a wall socket is deadly, do not do this except someone with electrician or electric powered engineer skills shows you procedures to do it. ===== each and everything has resistance at conventional temperatures, even empty area; the physicists call it the function impedance of a vacuum. Superconductors haven't any resistance, yet extremely chilly temperatures are necessary to create a superconductor and do something sensible with it. Too expensive for living house use.

Answer 5

If you are talking Ohm's law (http://www.physics.uoguelph.ca/tutorials/ohm/Q.ohm.intro.html)
V=IR therefore if your resistance is large, your voltage must be very high.

I would check out http://membres.lycos.fr/plasmapropulsion/Historical_&_Basic/Electric_Wind.htm

It looks like you are going to need a decent voltage power supply and an area of high curvature to give you that field strength.

Yes, you will need a considerable voltage to get that kind of current. Areas of high curvature tend to have higher field strengths,so that is why the experiment shows the fine point of the conductor causing that effect.

Answer 6

I believe that you are going to need several thousand volts. the easiest way to get that is to find a high voltage lab power supply, but you could make your own transformer if you had the time. Check winkipedia for more information about transformers. Your current of .5 amps is probably a bit high as the watts equal the volts times the amps. You are going to need about a kilowatt. For more information about ionic wind try searching for "lifter" on the web. people make them all the time out of aluminium foil and balsa wood. A word of caution, lots of them don't understand it and attribute it to a break through in gravity research.

Answer 7

According to what i have learnt voltage =current/resistance
The symbol of voltage is "V" .Symbol of current & resistance is "I" & " R" resp.
so V=I/R
Acc to ur question I=0.5A & R is very high.So Volage will be very small
To increase your voltage either increase your current or decrease your resistance.

Answer 8

ohm's law

V = I x R

Where:
V = Voltage
I = Current
R = Resistance