2006-07-10 16:31:32 · 11 answers · asked by michaelx99 1 in Education & Reference ➔ Homework Help
let those 5 consecutive numbers be x, (x+1), (x+2), (x+3), (x+4)
x + (x+1) + (x+2) + (x+3) + (x+4) = 900
5x+10=900
5x=890
x=178
therefore, those 5 numbers are 178, 179, 180, 181 and 182.
2006-07-11 02:21:30 · answer #1 · answered by R@inY 3 · 2⤊ 0⤋
178+179+180+181+182 = 900
2006-07-10 16:36:57 · answer #2 · answered by lovingdaddyof2 4 · 0⤊ 0⤋
900\5=180 thus the middle number so 178+179+180+181+182=900
2006-07-10 17:15:56 · answer #3 · answered by Charlie P 1 · 0⤊ 0⤋
900 / 5 = 180. That gives you the middle number. So it's
178 + 179 + 180 + 181 + 182 = 900
2006-07-10 16:38:47 · answer #4 · answered by Rich B 3 · 0⤊ 0⤋
900/5 = 180
178 + 179 + 180 + 181 + 182 = 900
2006-07-10 16:38:05 · answer #5 · answered by Kookiemon 6 · 0⤊ 0⤋
178 179 180 181 182
2006-07-10 17:28:29 · answer #6 · answered by Megan 1 · 0⤊ 0⤋
x + (x+1) + (x+2) + (x+3) + (x+4) = 900
5x+10 = 900
5x=890
x=178
178+179+180+181+182=900
2006-07-10 16:38:42 · answer #7 · answered by David B 1 · 0⤊ 0⤋
178 thru 182 = 900
2006-07-10 16:40:51 · answer #8 · answered by stacypeacock1967 3 · 0⤊ 0⤋
178, 179, 180, 181 182
2006-07-10 16:37:43 · answer #9 · answered by feeshbulb 2 · 0⤊ 0⤋
consider 5 consecutive numbers: a, b, c, d, e
a+b+c+d+e=900
because they are consecutive, you can write these relations:
b=a+1
c=b+1=(a+1)+1=a+2
d=c+1=(a+2)+1=a+3
e=d+1=(a+3)+1=a+4
a+(a+1)+(a+2)+(a+3)+(a+4)=900
5a+10=900
5a=900-10=890
a=890/5=178
b=a+1=178+1=179
c=a+2=178+2=180
d=a+3=178+3=181
e=a+4=178+4=182
(178,179,180,181,182)
2006-07-11 09:46:24 · answer #10 · answered by dianna30eur 1 · 0⤊ 0⤋