Five different eggs are to be shared completely between David and Nicole. The egggs are to be shared between them in such a way that no egg is broken, and each gets at least one egg. The number of different ways of sharing the eggs is:
a. 5
b. 25
c. 30
d. 31
e. 28
2006-07-10 13:06:10 · 12 answers · asked by hello 2 in Science & Mathematics ➔ Mathematics
Label the eggs A, B, C, D and E.
If David gets exactly one egg, this can happen in any of 5 ways.
If David gets exactly two eggs, this can happen in 5C2 = 10 ways.
If David gets exactly three eggs, this can happen in 5C3 = 10 ways.
If David gets exactly four eggs, this can happen in 5C4 = 5 ways.
David cannot get zero eggs, nor can he get five.
5+10+10+5=30
2006-07-10 13:16:46 · answer #1 · answered by fcas80 7 · 2⤊ 0⤋
Lets say these eggs are names 1 , 2, 3, 4, 5
David could get 1, 12, 13, 14 ,15, 123, 124, 125, 134,135 ,145, 1234, 1235,12345,0
so David has 15 different options
and Nicole can have the same thing
so Nicole has 15 different options
in total, I'm pretty sure The number of different ways of sharing the eggs is c. 30
correct me if i'm wrong though
2006-07-10 13:13:50 · answer #2 · answered by Eng 5 · 0⤊ 0⤋
David can have 1, 2, 3, or 4 eggs... Nicole gets the rest.
If David has one egg, he has 5 choices.
If David has two eggs, he has 10 choices. (You could use the formula for combinations here, or just count them... David gets eggs 1 and 2, 1 and 3, 1 and 4... and so on to eggs 4 and 5.)
If David has three eggs, Nicole has two, and her choices would be from the same possibilities as David's when he had two. There are 10 choices.
If David has four eggs, Nicole has one, and her choices would be from the same possibilities as David's when he had one. There are 5 choices.
Total possibilities = 5 + 10 + 10 + 5 = 30. Your answer is "c."
2006-07-10 13:14:29 · answer #3 · answered by Anonymous · 0⤊ 0⤋
If the eggs are not distinct, there are 4 ways to share: David either gets 1, 2, 3, or 4 eggs and Nicole gets the rest. Since that's not a choice, the eggs must be distinct.
So there are 5 choices of egg if David gets 1 (5C1), 10 choices if he gets 2 (5C2), 10 choices if he gets 3 (5C3), and 5 choices if he gets 4 (5C4), for a total of 30.
2006-07-10 13:18:48 · answer #4 · answered by Philo 7 · 0⤊ 0⤋
25
2006-07-10 13:15:32 · answer #5 · answered by Critical Mass 4 · 0⤊ 0⤋
Are they chicken eggs or rabbit eggs and does it count if you make them into an omelette and then cut up the omelette? Ask your teacher for the full information and resubmit the question.
If it helps you, draw a diagram or table and you'll see what the answer is assuming you slept through the permutations and combinations class which is a much easier way of solving this.
2006-07-10 13:12:23 · answer #6 · answered by Anonymous · 0⤊ 0⤋
If NO egg is broken, and they have be shared "completely", then they both have to share all 5 eggs. Answer: A. (It's not a math question really, it's a logic question...which, okay IS a type of math).
2006-07-10 13:12:09 · answer #7 · answered by stevenB 4 · 0⤊ 0⤋
0. This David hates eggs.
2006-07-10 13:09:31 · answer #8 · answered by Anonymous · 0⤊ 0⤋
A.5 u put all of the posibble combinations together and u get 5
2006-07-10 13:42:56 · answer #9 · answered by Anonymous · 0⤊ 0⤋
c.30
2006-07-10 13:37:10 · answer #10 · answered by DORK-Daughter of the Risen King 2 · 0⤊ 0⤋