How do you remove the modulus sign for the following problem?: |-3t+51|=?

Answer 1

|-3t+51|

if -3t+51>0, then |-3t+51|= -3t+51
if -3t+51<0, then |-3t+51|= -(-3t+51)

Answer 2

You solve the equation for both positive and negative results.

-3t + 51 = s
-3t + 51 = -s

Answer 3

I think in this case, the modulus sign means magnitude. The magnitude, |a+b| = (a^2 + b^2)^(1/2). Therefore, the magnitude of that expression is (9t^2 +2601)^(1/2). Of course, the modulus sign could also mean the positive (absolute) value of that expression, and that number depends on the value of t.