A die is rolled five times. What is the probability of getting 5 twos?

Answer 1

1/6 x 1/6 x 1/6 x 1/6 x 1/6

Answer 2

Assuming a 6-sided die with sides numbered 1-6, probability of 5 twos in 5 rolls is (1/6)^5 = 1/7776 = 0.0001286

Answer 3

The probability of rolling one die and getting a 2 is 1-in-6

The probablility of rolling two dice and getting a double-2 is 1-in-6 squared, or 1-in-36

The probability of rolling five dice and getting 5 twos is 1-in-6 to the fifth power, or 1-in-7776

Answer 4

i will get you by potential of part of it, yet there is one aspect i'm slightly fuzzy on. First issues first (assuming a 6-sided die), total sort of achievable consequences: 6^12. Now how about favorable consequences? a positive effect has 4 even numbers, 4 fives, and four non-5 unusual numbers. There are 3^4 procedures to roll the 4 even numbers, one thanks to roll the 4 fives, and a pair of^4 procedures to roll the non-5 unusual numbers. So acceptable this second it sort of appears like we've (3^4)(a million)(2^4)/(6^12) = a million/(6^8). regardless of the indisputable fact that, i'm no longer efficient if the roll order between the three instruments needs to be seen. i imagine the dice are distinguishable, so as that volume is the awesome result yet i'm no longer one hundred% efficient. Edit: i imagine fcas80 is sweet, and the procedures in which each and each and every of the 4 slots ought to correctly be chosen needs to be considered. So (12C4)(8C4)(4C4)/(6^8)

Answer 5

1/6 to the 5th power = 1/7776

Answer 6

1/6 to the 5th power = 1/7776

Answer 7

(1/6) to the power of 5
1/7776

I wouldn't bet on getting that if i were you, and if you do, check if the dice is loaded, the chances (one out of every 7776 rolls) is considered impossible

Answer 8

1/(6^5)

Answer 9

(1/6)^5=1/7776

Answer 10

why??