is 12 ohms and the resistance of the other device is 4 ohms, the total resistance of the two devices is..?
A. 0.625 ohms
B. 0.333 ohms
C. 3 ohms
D. 16 ohms
2006-07-10 09:07:04 · 6 answers · asked by Andrea 3 in Science & Mathematics ➔ Physics
The total resistance is ( 1/ (1/12 + 1/4))
or 1 / (1+3)/12
or 1/ (4/12)
or 1/(1/3)
or 3 ohms
2006-07-10 09:17:59 · answer #1 · answered by sebekhoteph 3 · 3⤊ 0⤋
In a parallel circuit risistance is calculated as 1/R1 + 1/R2 =1/Rtotal. 1/4 = 3/12 + 1/12 = 4/12 1/Rtotal = 4/12 so Rtotal = 12/4 = 3 ohms.
2006-07-10 11:46:47 · answer #2 · answered by physandchemteach 7 · 0⤊ 0⤋
C: 3 Ohms
2006-07-10 09:12:23 · answer #3 · answered by akash_dun 2 · 0⤊ 0⤋
For only two resistors, a variation of the original formula is
(R1R2)/(R1+R2)
( 12 * 4) / (12+4)
48/16 = 3 ohms (C)
2006-07-11 08:13:07 · answer #4 · answered by flandargo 5 · 0⤊ 0⤋
I'm thinking that is B, but it's been a while since I was in physics.
Isn't this the formula for total parallel resistance: 1 / R(total) = (1 / R1) + (1 / R2)
2006-07-10 09:15:12 · answer #5 · answered by WEIRDRELATIVES 5 · 0⤊ 0⤋
The way the question is worded, 16 ohms.
I think, however, you want the resistence of the entire circuit, which, is probably C, though I haven't done electric circuits in awhile.
2006-07-10 09:13:34 · answer #6 · answered by bequalming 5 · 0⤊ 0⤋