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11 answers

1/24 = 1/R1 + 1/97

1/24 - 1/97 = 1/R1

73/2328 = 1/R1

2328/73 = R1

2006-07-10 06:01:48 · answer #1 · answered by jimvalentinojr 6 · 0 0

Assuming you want to solve it for R you get:

R = 1/(1/R1 + 1/R2) which is easy enough on a calculator.

Plug in the numbers and you get:

R = 1/(1/24 + 1/97) = 1/(.051976) = 19.23967

If this was an algebra or fractions problem and not a physics problem, the teacher might prefer the answer as a fraction.

In that case, the formula would look like:

R = (R1 + R2)/(R1*R2) = (24 + 97)/(24 * 97)

2006-07-10 06:04:41 · answer #2 · answered by tbolling2 4 · 0 0

You have a couple answers that agree, but a number that do not....I wonder which are correct.

Let's simplify the problem, and do the algebra frist and plug the numbers in last.

Let 1/R = 1/R1 + 1/R2 be written as: 1/a = 1/b + 1/c, and we need to find "b" (R1).

1/a = 1/b + 1/c
==> b = ac/(a + c)

Which is: R1 = RR2/(R + R2)

Now, plug in your numbers:

R = 24
R2 = 97

You get....

....R = 19.23

2006-07-10 07:25:03 · answer #3 · answered by Anonymous · 0 0

This seems like a resistors in parallel question.

1/24 = 1/R1 + 1/97
1/24 - 1/97 = 1/R1
73/2328 = 1/R1

You can cross multiply to get the value or just inverse 73/2328 to get R1.

2006-07-10 06:05:21 · answer #4 · answered by Anonymous · 0 0

You better not be cheating on your homework...
Try this:
1. Move R1 to a side by itself

1/R1 = 1/R - 1/R2

2. Make the right side one whole fraction:
1/R1 = R2/(R*R2) - R/(R*R2) = (R2-R)/(R*R2)

Flip it and plug in numbers:
R1 = (R*R2)/(R2-R) = (24*97)/(97-24)=2328/73

2006-07-10 06:08:14 · answer #5 · answered by ymingy@sbcglobal.net 4 · 0 0

Multiply the two aspects of the equation by employing R(r1)(r2). Upon doing so, you've gotten r1r2 = Rr2 + Rr1. we'd want to isolate r1, so deliver all r1 words to the same part. r1r2 - Rr1 = Rr2. factor out r1, so r1(r2 - R) = Rr2. Now divide by employing r2 - R r1 = (Rr2)/(r2 - R)

2016-12-10 07:26:08 · answer #6 · answered by Anonymous · 0 0

Just use a calculator

Inverse of (1/24)+(1/97)

19.24

2006-07-10 06:02:39 · answer #7 · answered by justwebbrowsing 3 · 0 0

1/R = 1/R1 + 1/R2

1/24 = 1/R1 + 1/97

1/24 - 1/97 = 1/R1

97 - 24
----------- = 1/R1
24 * 97

73/2328 = 1/R1

R1 = 2328 / 73 = 31.89

2006-07-10 06:03:56 · answer #8 · answered by JK 2 · 0 0

1/R = 1/R1 + 1/R2

1/R - 1/R2 = 1/R1

1/R * R2/R2 - 1/R2 * R/R= 1/R1

R2/R*R2 - R/R*R2 = 1/R1

(R2 - R) / R*R2 = 1/R1

R*R2 / (R2-R) = R1

24*97 / (97-24) = 31.89

hope that helps! :-)

2006-07-10 06:07:15 · answer #9 · answered by bablunt 3 · 0 0

er - in a word NO

my brain hurts now...

what IS that anyway?

sorry I couldn't help...

2006-07-10 06:02:31 · answer #10 · answered by Mrsdanieljackson 3 · 0 0

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