2006-07-09 20:04:33 · 6 answers · asked by Brent M 1 in Science & Mathematics ➔ Mathematics
55. You add the numbers up and then divide by the number of numbers.
2006-07-09 20:13:25 · answer #1 · answered by Eric X 5 · 0⤊ 0⤋
Divide the sum of those by how many there are. So 57+64+20+33+106+50=330. The the average would be 330 divided by 6. So 55.
2006-07-09 20:09:10 · answer #2 · answered by jetteleigh 2 · 0⤊ 0⤋
Average number of employees in the department=summation of employees in all six departments divided by number of departments.
= 57+64+20+33+106+50/6
=330/6
=55.
so, average no. of employees in department is 55.
2006-07-09 20:23:51 · answer #3 · answered by Anonymous · 0⤊ 0⤋
55
2006-07-09 20:09:14 · answer #4 · answered by dolph002 2 · 0⤊ 0⤋
SO U HAVE 6 DEP AND U WANT AVG OF EMPLOYEES
FOR CALCULATING THE AVG U HAVE FORMULA
AVG = (TOTAL(SUM) OF THE NUMBER GIVEN) / NUMBER
SO AVG OF UR QUS BE
AVG = (57+64+20+33+106+50)/6
AVG = 330/6
AVG = 55 NUMBER OF EMPLOYEES
UR ANS GOT IT
2006-07-09 21:03:38 · answer #5 · answered by thakur4u5 2 · 0⤊ 0⤋
I think it is 55
2006-07-09 20:15:59 · answer #6 · answered by Dan 1 · 0⤊ 0⤋