algebraically speaking..?
2006-07-09 17:01:05 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Physics
V^2 = V0^2 +2ax
V^2 - V0^2 = 2ax
V^2 - V0^2/2x = a, and that's the answer!
2006-07-09 17:06:16 · answer #1 · answered by K.P. 3 · 0⤊ 0⤋
subtract Vo squared from both sides leaving only 2ax on the right. Now divide both sides by 2x leaving only a on the right and (V^2 - Vo^2)/2x on the left
2006-07-10 00:08:37 · answer #2 · answered by wvl 3 · 0⤊ 0⤋
v^2 = v0^2 + 2ax
Subtract v0^2 from both sides:
v^2 - v0^2 = 2ax
Divide each side by 2x
(v^2 - v0^2) / 2x
= acceleration
2006-07-10 00:20:52 · answer #3 · answered by Anonymous · 0⤊ 0⤋
your solving for a so....
you subtract by V0^2 on both sides
then you divide both sides by 2x to get that answer.
2006-07-10 00:07:19 · answer #4 · answered by Anonymous · 0⤊ 0⤋