True or False: If f(x) is a strictly decreasing function defined for all values of x, then f(0) < f(1).?

Answer 1

If f is strictly decreasing, then the larger x is, the smaller f(x) is, so f(0)>f(1).

Therefore the answer is False.

Another way to see this is the proof through calculus (if f was differentialbe).

By the mean value theorem, there exists some c such that 0

Answer 2

Since f(x) is decreasing as x increases. Then f(0) < f(1) is false.

f(x) = -x is an example of such a function.
f(0) = 0
f(1) = -1
0 < -1 is false

Answer 3

a million. you in simple terms about threw the e book even as interpreting Order of the Phoenix because of Umbridge's moves pretend 2. a number of the flaws Draco stated about Harry were authentic authentic 3. Harry will be someone you could get alongside with pretend ( I in simple terms do not have the persistence for that. =/ ) 4. without Luna, the books doesn't be an same authentic 5. Hermione aggravated you commonly authentic 6. You felt undesirable for Bellatrix pretend 7. You cheered even as Voldemort died authentic 8. Ron Weasley is tremendous! authentic

Answer 4

f(0)is 0 and has no assigned value and f(1) is therefore > f(0).
The ans. then must be true.

Answer 5

False.

By definition of a decreasing function,

when x gets larger,

the f(x) gets smaller.

Given x1 and x2, such that x1 < x2 (note: x gets larger)

Then f(x1) > f(x2) (note: f(x) gets smaller)