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Suppose that F(x)=f(g(x)) and g(18)=17,g'(18)=19,f'(18)=14 and f'(17)=5,find F'(18)?I calculated u sing the chain ruleand i came up with 4522,
F(g(x))=f'(g(X)).g'(X)
(14.17)19
4522
did i do it right?

2006-07-09 12:06:19 · 4 answers · asked by lisa 1 in Science & Mathematics Mathematics

4 answers

the rule is right, its implementation is wrong

f'(g(x)).g'(x)
= f'(g(18)).g'(18)
=f'(17).g'(18)
=5.19
=95

2006-07-09 12:12:32 · answer #1 · answered by alia_vahed 3 · 1 0

ok so if u wanted to find F'(18), using chain rule, that is same as finding f'(g(18))*g'(18).
this is equal to 19 * f'(17), which is equal to 19*5 = 95.

so u did it right up till the (14.17)19
f'(g(x)) means u have to find what g(x) is (in this case its 17) and then find f'(x) at that number (so u have to find f'(17)). and then multiply by the 19.

i hope u get that. its kinda hard to explain but ya. laterz

2006-07-09 19:14:19 · answer #2 · answered by Anonymous · 0 0

The answer is 95 by using the chain rule and simple substitution

It results in 19 * 5 = 95

2006-07-09 19:31:40 · answer #3 · answered by icehoundxx 6 · 0 0

Not quite. You have the chain rule correct, but you need to watch out for the values.

F'(18) = [f(g(18))] = f'(g(18)) * g'(18)
= f'(17) * 19
= 5 * 19
F'(18) = 95

The f'(18) isn't need.

2006-07-09 19:14:10 · answer #4 · answered by Ѕємι~Мαđ ŠçїєŋŧιѕТ 6 · 0 0

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