how long will freefall last if ur at the top of a 30000 feet buliiding in an elevator top floor when da cord s

Question

when da cored snappes at top floor

Answer 1

X=1/2AT^2
X=30,000 feet.
A=32 feet per second squared.
30,000=1/2*32*T^2
30,000*2/32=T^2
1,875=T^2
T=43.3 seconds.
Neglecting air resistance.

Answer 2

Objects fall due to gravity, and the formula for figuring that out is:

S=1/2 GT² where the force of gravity makes anything fall at the rate of 32 ft. per second per second or 32 ft per second squared. So you take an elevator at the top of a 30,000 foot tall building and you plug in the numbers. What you need to know is how long a time it takes for the elevator to hit the bottom and then you square that time and multiply it times 32 and divide the whole thing by 2 and you will come up with S which is the Speed the object was going when it hit. You see, the speed increases exponentially with the time something is falling.

I think that you need to have the time to do this equation. I am not a mathematics expert, so these are only my ideas. Maybe somebody else has a better idea.

You could also apply the formula V=AT or Velocity equals Aceleration Times The time, where Velocity= Aceleration (which is the aceleration due to gravity times the time in seconds. In any event, you will get an answer in feet per second and you will have to convert that into miles per hour for your final answer. The best formula to use is S=1/2gt² where Speed = 1/2 x 32 x t² where t is in seconds.

Answer 3

I see everyone wants to neglect air resistance, but that isn't what happens in the real world, now is it!?

Since air resistance does come into play, after accelerating, the elevator would reach a max speed of approximately 200mph. This is called terminal velocity.

200mph = 293.3 ft/sec.

So it would take 9.167 sec. to reach 293.3 ft/sec since:

V = Vo + at --> 293.3 = 32t solve for t to get 293.3 ft/sec. Initial velocity Vo is 0.

OK, how much distance did that take:

S = So + Vot + ½at² so both So = Vo = 0 so we get:

S = ½at² we know both a and t so plug and chug to get

S = 1344.5ft.

Now for the rest of the story. The remaining distance to fall is:

30000ft - 1344.54 ft and you've used 9.167 seconds so far.

That leaves a distance of 28655.46 feet to finish falling. Since we are at terminal velocity of ~200mph or 293.3 ft/sec, then this final part simply is a division problem.

s = vt so t = s/v = 28655.46ft/293.3ft/sec = 97.69 seconds

so the total time for the elevator to drop would be 97.69sec + 9.16sec = 108.65 seconds or approximately

1 minute and 49 seconds.

When we dropped the A-bomb on Hiroshima, the plane was at 33000 ft and the bomb dropped ~45 seconds before it detonated at about 1600ft above the city. Of course the bomb was more aerodynamic than the elevator so its terminal velocity would be higher. It's straight down velocity would still have been the same if it had been dropped straight downward from an airplane that wasn't moving because velocity in the x and y axes are INDEPENDENT!

Answer 4

You are all wrong! LOL

Elevators have "Safety" measures to prevent "Freefall" you will fall approximately 1 story and be stopped by the "Safety Mechanism". 8-) Fall time less than 1 second.

Uhh........since the "dacord" snapped the "Safety Mechanisms" on the Car will stop you.

Answer 5

Forget all the math formulas, your free fall would late almost 3 mins. Long enough for you to crap in you pants and change them, if you hurryed before hitting ground floor.

Answer 6

let S=distance, U=initial speed, t=time
s=U*t+0.5*a*t^2 (eq1)
Assume initial speed = 0, a = 9.8 m/s (avg grav accel)
so U*t = 0
re-arrange eq1:
t = squarerout(2*S/a)
now, 30000 ft = 9146 m
so t = squarerout(2*9146/9.8)
= 43.2 seconds
The above neglects air resistance (true only for a vacuume)

Answer 7

We could all answer your question if you could present it in a language that was "readable"...but your words make absolutely no sense!