How do you balance this equation?

Question

C5H10 (g) + O2 (g) ---> CO2 (g) + H20 (l)
Please show me step by step, I am having trouble understanding this.

Answer 1

I use a 4 step process:

1) Balance the carbon
C5H10 + O2 ---> (5)CO2 + H2O

2) Balance the hydrogen
C5H10 + O2 ---> 5CO2 + (5)H2O

3) Count and balance the oxygen
(15 oxygen on right side)
C5H10 + (7.5)O2 ---> 5CO2 + 5H2O

4) Double all of the coefficients if the oxygen coefficient is not a whole number
2C5H10 + 15O2 ---> 10CO2 + 10H2O

Answer 2

Unbalanced, we start with
C5H10 + O2 -> C02 + H20
The left side has 10 H, To balance out H
C5H10 + O2 -> C02 + 5H20
The left side has 5C, To balance out C
C5H10 + O2 -> 5C02 + 5H20
The right side has 15 O, To balance out O
C5H10 + (71/2) O2 -> 5 C02 + 5 H20
Since we cannot use 1/2 for a molecule, multiply everything by 2
2C5H10 + 7 O2 -> 10 C02 + 10H20

Answer 3

2 C5H10 + 20 O2 ----> 10 CO2 + 20 H20

in the begining there are
10 Carbon atoms
20 hydrogen atoms and
40 oxygen atoms

in the end there are
10 carbon atoms
20 hydrogen atoms and
40 oxygen atoms (20 in co2 and 20 in h2o)

Answer 4

here basically number of atoms of each kind on left hand side must be equal to that on right hand side.
C5H10(g) + O2(g).............> 5CO2(g) + H2O(l) {let us make number of carbon atoms equal on both sides.}
C5H10(g) + O2(g)............> 5CO2(g) +5H2O(l) {let us make hydrogen atoms equal on both sides}
C5H10(g) + 5/2 O2(g).........> 5CO2(g) + 5H2O(l){ make oxygen atoms equal on both side.}
multiply whole equation by 2 to remove fraction
2C5H10(g) + 5O2(g) .........> 10CO2(g) + 10H2O(l)

Answer 5

c5h10(g) + o2(g)---->co2(g) + h2o(l)
1. break it down to the elements on each side of the reaction
5c 10h 2o ____> 1c 2h 3o you need to 5x co2
c5h10(g) + o2(g) ____>5co2(g) + h2o(l)
5c 10h 2o _____> 5c 11o 2h you need to go 5x h
to balance out but that would give
you an odd number of o so 10x
c5h10(g) + o2(g)____> 5co2(g) + 10h2o(l)
5c 10h 2o ____> 5c 20h 20o you need to 2x the h on
left side but that will also give you 10c
so you will have 2x co2
2c5h10(g) + o2(g)----->10co2(g) + 10h2o(l)
10c 20h 2o -----> 10c 20h 30o 15x o2 on left side
2c5h10(g) + 15o2(g) ------> 10co2(g) + 10h2o(l)

Answer 6

andrewxaverian is correct. the other two are idiots.