There are 6 sides to a dice, each time you throw, only one side will face up. So, the total outcomes for 2 die thrown is actually (6C1) x (6C1), [where 6C1 means 6 combination 1],
Your other proposed solution 12C2, is used only for situation where there are 12 balls numbered between 1 to 12 in a bag, and drawing 2 balls from the bag, what is total number of possibilities of different combinations there are.
2006-07-09 00:42:19
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answer #3
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answered by Sentient 2
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The only possible outcomes are :
(1,1),(1,2),(1,3),(1,4),(1,5),(1,6)
(2,1),(2,2),(2,3),(2,4),(2,5),(2,6)
(3,1),(3,2),(3,3),(3,4),(3,5),(3,6)
(4,1),(4,2),(4,3),(4,4),(4,5),(4,6)
(5,1),(5,2),(5,3),(5,4),(5,5),(5,6)
(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)
ie only 36 outcomes.12 combinations of 2 doesn't make sense.
2006-07-09 00:40:00
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answer #8
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answered by coolzadar 2
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