what is x/3 + y/5=6 and 2x/5 + y/2=-4 using elimination method of linear equation answer this plz...?

Question

pls. show the solution and checking its not my homework because its my friends question

Answer 1

do your own homework.. hehe.

Answer 2

x/3 + y/5 = 6
2x/5 + y/2 = -4

First, eliminate fractions:

15(x/3 + y/5 = 6) ----> 5x + 3y = 90
10(2x/5 + y/2 = -4) -----> 4x + 5y = -40

To eliminate, you need to add the two equations together. But before you can add them, you have to multiply one equation by another number. You do this so two terms with the same variable cancel or eliminate:

(-4/5) * (5x + 3y = 90)

-4x - (12/5)y = -72 Now add the two equations
4x + 5y = -40

0 + 13/5 y = -112

y = - 560 / 13
Plus this number back into one of the original equations and solve for x

Answer 3

Hmm.. substitution method would be easier here, but if you insist on elimination method, here goes:

x/3 + y/5 = 6
multiplying throughout by 5, you get
5x/3 + y = 30 ----------(1)

2x/5+y/2 = -4
multiplying throughout by 2, you get
4x/5 + y = -8 ----------(2)

So you take equation (1) minus equation(2), you get

5x / 3 + y - 4x/5 - y = 30 - (-8)
13x/15 = 38
x =570 / 13

Then you substitute this value for x into equation (1) or (2), and solve for y.
Good luck!

Answer 4

x/3 +y/5=6-----(1)
2x/5 + y/2=-4-----(2).
Now take (1), the LCM of the denominators 3 and 5 is 15. So multiply both sides by 15. we get
5x + 3y=90-----(3)
Take (2), the LCM of 2 and 5 is 10. Multiply both sides by 10. we get
4x+5y=-40 ----(4)
Let us eliminate x's from the eqns 3 and 4. The x-coefficients in eqn(3) and (4) are 5 and 4. The LCM of 5 and 4 is 20. Let us make the x-coefficients as 20. i.e. multiply eqn(3) by 4 and eqn(4) by 5.
(3)*4------>20x+12y=360------(5)
(4)*5------>20x+25y=-200-----(6)
Substitute (4) from (3), we get -13y=560
y=-560/13.
From (4), 4x-2800/13=-40
4x=-40+2800/13
=(-520+2800)/13=2280/13
x=2280/(4*13)=570/13

Answer 5

x/3 + y/5 = 6
2x/5 + y/2 = 4

taking the L.C.M.

15x + 3y = 90 eqaution 1
4x + 5y = 40 eqaution 2

multiply equation 1 with 5 and eqation 2 with 3 which results in

75x + 15y = 450 eq 3
12x + 15y = 120 eq 4

substract eq 3 from 4

63x = 330

x = 330/63
simplify it and substitute its value in eq 1
you will get the answer

Answer 6

equation 1
x/3+y/5=6
5x+3y=90 }x5
23x+15y=450

equation 2
2x/5+y/2=-4
4x+5y=-40 }x3
12x+15y= - 120

now eliminate the y and find the x..
Good Luck!!

Answer 7

x/3 + y/5=6
5x+3y=90
(25/3)x+5y=150 (1)

4x+5y=-40 (2)

(1)-(2)

(25/3)x-4x=150+40
(13/3)x=190
x=570/13

y=-560/13