Show work on how answer was achieved.
2006-07-08 23:49:18 · 5 answers · asked by Daniel R 1 in Science & Mathematics ➔ Mathematics
Sherman81 is right. We need not take up long division. But what is the section in which the child's homework is? I think long division. The child wants the long division. In Math section, many homework questiona are posted, asking to show total detailed work which indicates it is homework.
2006-07-09 03:16:33 · answer #1 · answered by K N Swamy 3 · 0⤊ 0⤋
It's very difficult to show it in this silly text window. However, I try to explain it:
First, we consider 5x^3 to be divided to x-3. It is obvious that a quotient factor of 5x^2 should be considered. Multiplying 5x^2 by the divisor we get 5x^3 - 15x^2 which should be subtracted from the divided. This yields the divided become 15x^2+10x +1 which should be divided by x-3. Again the next factor of quotient would be 15x. Multiplying by divisor and subtracting from divided leaves a 55x+1 as the remainder. The last step leaves 55 at quotient and 166 at remainder. So:
5x^3-5x+1=(5x^2+15x+55)(x-3)+166
2006-07-09 01:07:34 · answer #2 · answered by fredy1969 3 · 0⤊ 0⤋
Woah you've got to use long division for this. I can't show working in this limited space, but the answer is this:
5x^2 + 15x +40
Remainder: 121
2006-07-09 00:15:10 · answer #3 · answered by Sentient 2 · 0⤊ 0⤋
(5x^3 - 5x + 1)/(x - 3)
3`|`5`0``-5`|`````1
```|``15`45`|``120
----------------------
```|`5`15`40`|`121
ANS : 5x^2 + 15x + 40 R (121) or 5x^2 + 15x + 40 + (121/(x - 3))
2006-07-09 01:51:00 · answer #4 · answered by Sherman81 6 · 0⤊ 0⤋
X
2006-07-09 00:35:36 · answer #5 · answered by Spike Spiegel 4 · 0⤊ 0⤋