If Jim M is reading this, I didn't get it right when I answered his question. Sorry Jim.
U/n, when U = 1 and n = any number or fraction except 0. This definition gives us the + & - counting numbers and fractions (a.k.a. valency scale).
U/n, when U = any number except zero and n = 0. The outcomes here are indefinite*. This gives us the ordinal or structuring scale (the quotients are place-holders, not numbers).
*Unless 0/0 = 1. Consider: n/n = 1, and if 0 is a number then 0/0 = 1.
U/n, where U = x and n = 1. This gives us the cardinal or measuring scale. For any value of x the quotient is 1. Values of x are dependent upon what is being measured and choice of measuring unit determines choice of x (e.g. one yard, one metre, etc.)
2006-07-08 20:10:29 · 14 answers · asked by brucebirdfield 4 in Science & Mathematics ➔ Mathematics
u went wrong in the second step... U= any number except 0 or infinity and it shouldnt be a fraction. It should be a real number.
In the fourth step 0/0 is not equal to one...becoz 0/0 = 0 ...if n/n =1 then n can be any number except zero ...1/infinity = 0 which doesnt imply in your condition....
2006-07-08 20:20:32 · answer #1 · answered by Anonymous · 0⤊ 2⤋
I didn't check the details, but the biggest error is your hyphothesis on devision by zero. Devision by zero is undefined, under all circumstances. Think of it as being the outcome of the rules of devision and multiplication - eg:
20/5 = 4 implies 4*5 = 20.
now devision by zero:
20/0 = z implies z*0 = 20 - what number multiplied by zero = 20?
You can multiply 0 by 10000000000000000000 and still get zero.
Division by zero in UNDEFINED - and that's a fact. 0/0 is not 1, it is undefined
2006-07-08 23:38:30 · answer #2 · answered by Engineering_rules 2 · 0⤊ 0⤋
16t^2 + 5t - 159 = 0 16 ought to correctly be written as 16 x a million and 159 as fifty 3 x 3 16 x 3 will be 40 8 and fifty 3 - 40 8 = 5 So, we are able to component the equation as (t - 3) (16t + fifty 3) = 0 So, t = + 3 and - fifty 3/16 i wish you understood the operating. in case you want extra help, digital mail me.
2016-11-01 11:59:06 · answer #3 · answered by ? 4 · 0⤊ 0⤋
where N ε R - {0}
R is the set of real numbers
0 / N = 0
N / 0 = ∞
0 / 0 is undefiende
2006-07-08 20:31:54 · answer #4 · answered by M. Abuhelwa 5 · 0⤊ 0⤋
Let n is non-zero.
0/n=0
n/0 is not defined.
0/0 is not determined.
n/n=1.
n/1=n.
2006-07-09 03:38:11 · answer #5 · answered by K N Swamy 3 · 0⤊ 0⤋
well to a great extent you wrote it right. but 0/0 is not allways 1.
for this you can refer calculus. or ask subsequent question.
2006-07-08 20:31:48 · answer #6 · answered by flori 4 · 0⤊ 0⤋
Sheeesh even if it wrong i give ya props cause i couldnt continue reading or even understand after the 3 line.........
2006-07-08 20:14:37 · answer #7 · answered by ♥ Raptors Fan 4 · 0⤊ 0⤋
dude its summer man go out with a girl man
2006-07-08 20:14:52 · answer #8 · answered by sin_823 2 · 0⤊ 0⤋
Just skimming over it, it looks correct to me.
2006-07-08 20:15:45 · answer #9 · answered by pgufs 3 · 0⤊ 0⤋
No. You had a few mistakes.
2006-07-09 02:10:47 · answer #10 · answered by Eric X 5 · 0⤊ 0⤋