please enter the value of f'(a)
2006-07-08 17:15:55 · 9 answers · asked by lisa 1 in Science & Mathematics ➔ Mathematics
There is actually a missing peice of information in your question. What is a? If a=x, then f(x)=f(a) and thus, f '(x)=f '(a). If this is actually the case, then you can solve the equation as follows:
f (x)=5+x-2x^2
f '(x)=1-4x. Thus,
f ' (a)=1-4a.
2006-07-08 17:34:12 · answer #1 · answered by Anonymous · 0⤊ 1⤋
The derivative of f(x) is
1-4x
f'(a) is 1-4a, where a is a constant number
2006-07-09 01:08:26 · answer #2 · answered by Supermatt100 4 · 0⤊ 0⤋
First find f(a).
f(a)= 5 + a - 2a^2
f'(a)= 1 - 4a
2006-07-09 00:32:31 · answer #3 · answered by thunderbomb90 3 · 0⤊ 0⤋
f(x)=5+x-2x^2
f '(x) = 1 - 4x
f '(a) = 1 - 4a
2006-07-09 01:18:03 · answer #4 · answered by Thermo 6 · 0⤊ 0⤋
f(a) = 5 + a - 2a^2
2006-07-09 00:23:03 · answer #5 · answered by tkquestion 7 · 0⤊ 0⤋
f'(x)=1-4x
therefore f'(a)=1-4a
2006-07-09 00:44:14 · answer #6 · answered by Sheet P 2 · 0⤊ 0⤋
f(a)=5+a-2a^2
2006-07-09 00:26:08 · answer #7 · answered by harunch2002 3 · 0⤊ 0⤋
f'(x)=1-4x
Thus f'(a)=1-4a
2006-07-09 00:27:59 · answer #8 · answered by Anonymous · 0⤊ 0⤋
f'(x)=1-4x
Thus f'(a)=1-4a
2006-07-09 00:17:14 · answer #9 · answered by Eulercrosser 4 · 0⤊ 0⤋