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This is a buffer question. The first step is to determine the moles of sodium acetate (molar mass = 82) 11/82 gives .134 moles of acetate ion. .290 L of .205M HCl gives .05945 moles of hydroxide ion. After the hydroxide reacts with the acetate ion to form acetic acid, there will be .07455 moles of acetate and .05945 moles of acetic acid. The Ka of acetic acid is 1.8 * 10^(-5). The buffer equation is:

[H+] = Ka (acid/base)

Plug in the numbers to determine the [H+].
[H+] = 1.43 * 10^(-5)
pH = 4.84

2006-07-08 13:31:20 · answer #1 · answered by andrewxaverian 2 · 0 0

Sorry, yet you won't be able to have a pH of a base it extremely is acidic. That makes no sense in any respect. If that is a base the pH might want to be > 7.00. The pH is 8.87. Sodium acetate is a base and this pH is ordinary. Kb = 5.55 x 10^-10 = x^2/(0.one hundred - x), the position x = [OH^-] remedy this employing the quadratic equation and also you get [OH^-] = 7.40 5 x 10^-6 [H^+][OH^-] = a million.00 x 10^-14 [H^+] = (a million.00 x 10^-14)/(7.40 5 x 10^-6) = a million.34 x 10^-9 M pH = -log(a million.34 x 10^-9) = 8.87 desire that's positive to you. JIL HIR

2016-11-06 01:52:36 · answer #2 · answered by ? 4 · 0 0

Do your own homework?

2006-07-08 13:35:03 · answer #3 · answered by Joshua 2 · 0 1

exactly

2006-07-08 14:11:53 · answer #4 · answered by Anonymous · 0 0

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