some say im obsessed with drugs, why.
2006-07-08 11:15:48 · 38 answers · asked by Marijuana Man 1 in Entertainment & Music ➔ Polls & Surveys
Look at my 360, for mo info
2006-07-08 11:21:36 · update #1
Because you can't spell??
2006-07-08 11:18:02 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Maybe it's the company you keep. Also, do you talk about drugs a lot BUT never talk about the dangers? That will make me think you are on drugs.
2006-07-08 11:18:31 · answer #2 · answered by Patty Pooh Pooh Pie 5 · 0⤊ 0⤋
Well, Hamster man, looking at your page, I am guessing that youare 1. obsessed with drugs, 2. young, 3. will grow out of hte, "hey look at me! I smoke weed!" phase of your life as most of us older folks did.
Good luck!
2006-07-08 11:26:44 · answer #3 · answered by risibility1956 3 · 0⤊ 0⤋
1) Your screen name.
2) Your spelling is poor
3) Your lack of punctuation and capitalization which all probably resulted from a lack of brain cells.
2006-07-08 15:02:13 · answer #4 · answered by loyerd6 4 · 0⤊ 0⤋
The drugs are effecting your memory. You just stated that you did them.
2006-07-08 11:19:34 · answer #5 · answered by older woman 5 · 0⤊ 0⤋
Because you keep touting your drug interests and preferences. Don't you remember?
Or, does the pot cause short-term memory loss?
2006-07-08 11:18:18 · answer #6 · answered by racingcowboy58 6 · 0⤊ 0⤋
Your name maybe. ANd your paranoid that everyone thinks you're on drugs?
2006-07-08 11:18:04 · answer #7 · answered by Anonymous · 0⤊ 0⤋
Um.. maby because you are, look at your 360 page and think about it.
2006-07-08 14:54:51 · answer #8 · answered by mfougnie 3 · 0⤊ 0⤋
maybe its because you are? I mean you did ask a question about drugs.
2006-07-08 11:17:04 · answer #9 · answered by Jester 5 · 0⤊ 0⤋
The fact that you have to ask this means that all that weed has finally fried your brain.
2006-07-08 14:14:00 · answer #10 · answered by SeeNoEvil 6 · 0⤊ 0⤋
Yeah, what's in a name anyway? It's just a name. what where we talking about?? ;0)
2006-07-08 12:07:26 · answer #11 · answered by Nora T 3 · 0⤊ 0⤋