The device is in the deepest part of the Pacific Ocean, which is approx. 35,000ft and how tall is the resulting tidalwave?
2006-07-08 10:50:59 · 4 answers · asked by Steel Rain 7 in Science & Mathematics ➔ Physics
around 100,000 nuatical mile squred
2006-07-08 10:55:53 · answer #1 · answered by Tyler B 1 · 0⤊ 0⤋
Good question. A lot I'm guessing. You'd need a few thing to calc this one:
1) Type of device (uranium or plutonium)
2) Temperature and Density of the water
[Volume of Water] = [Energy from Device] / [Energy to Vapourize 1 Volume Unit of Water]
I'll take a guess. 124,566 litres
2006-07-08 18:02:22 · answer #2 · answered by Anonymous · 0⤊ 0⤋
No water would be vaporized. At that depth any vapor would turn back to water before it reaches the surface.
I don't know about the tidal wave. Try it and see.
2006-07-08 18:21:16 · answer #3 · answered by Anonymous · 0⤊ 0⤋
it wouldnt vaporize it... it would be displaced, and the resulting wave would be the height of the CN tower
2006-07-08 17:57:06 · answer #4 · answered by Eric B 3 · 0⤊ 0⤋