domain of g(x)=6-6x/1+x?

Answer 1

Domain is values of "x" that work in the function.

In x + 5, the domain is all real numbers

In (6-6x)/(1+x), it would be also all real numbers, except you have a denominator in the function. A denominator cannot be zero, so actually set it equal to zero to determine what the domain cannot be.

x + 1 = 0 , x = - 1, but f(-1) = (6+ 6)/(1- 1) = 12 / 0

So the domain is x{(-infinity,0)U(0,infinity)}


Here's the range for later:

y = (6-6x)/(1+x) ---> exchange the variables

x = (6-6y)/(1+y) ----> and solve for "y"

x + xy = 6 - 6y
6 - x = xy + 6y
6 - x = y(x + 6)

y = (6 - x)/(6 + x) ----> as above, (6 + x) cannot = zero, so
x cannot equal -6
Switch the variables back, so its really y cannot = -6


Range is y{(-infinity,-6)U(-6,infinity)}

Answer 2

The area is going to be the numbers that you'll be able to plug into x and get a significant cost for y. Any actual volume will artwork for x. the variety is the numbers that you get for y once you install any achievable cost for x. you could locate that for significant values of x you get tremendous values of y. The values of y bypass as a lot as infinity. The question is, what's the minimum cost for y? There are a number of procedures of determining this. Graphing ought to help. Taking the spinoff ought to help, yet you ought to favor to carry close some calculus to ensure the spinoff. Or slightly trial and errror shows you that x=3 promises the minimum cost of y. At x=3 we've y = 3*3 - 6*3 + a million = -8. So the variety is -8 to infinity.

Answer 3

1 + x > 0
1 + x < 0

otherwise the denominator will be 0.

so

x > -1 and x < -1. x can't equal -1

Answer 4

The x may be anything but x=-1, because you can't divide by 0

Answer 5

all real numbers, all complex numbers, or whatever numbers you want to use.

if you mean g(x)=(6-6x)/(1+x), then it would be all real numbers excluding -1, complex numbers excluding -1 . . . or whatever you want to use; just not -1.

Answer 6

All real numbers : ] -∞ ; -1[ and ]-1; +∞[

Answer 7

if it's /(1+x), then doman is all numbers but -1