well, there are two roots the the functions f(x)=x^2-π^2. Those roots are π and -π.
2006-07-08 08:21:35
·
answer #1
·
answered by Eulercrosser 4
·
3⤊
4⤋
I have no idea
the square roots of PI squared are of course PI and -PI.
but pie squared?
I once ate some rootabaga pie. that might come into it somehow
2006-07-08 15:23:08
·
answer #2
·
answered by enginerd 6
·
0⤊
0⤋
Whenever a number squared is placed under a radical is itself.
So, the square root of pi squared is pi.
2006-07-08 15:49:43
·
answer #3
·
answered by Anonymous
·
0⤊
0⤋
there is a property in math:
Sq rt(x squared)= absolute vaue of x. (the number w/o the sign)
let x=pi
so Sq rt(pi squared)=absolute value of pi = pi.
2006-07-08 15:42:33
·
answer #4
·
answered by dennis_d_wurm 4
·
0⤊
0⤋
well if u square it then square root the anwser wouldnt it be pi?
2006-07-08 17:30:25
·
answer #5
·
answered by mountianbiker_dude 2
·
0⤊
0⤋
+pi. Pi is usually defined as a ratio of circle measurements, so only +pi is relevant.
2006-07-08 18:39:32
·
answer #6
·
answered by Anonymous
·
0⤊
0⤋
pi. oops on the "you're" spelling for "your math".
i am not math.
2006-07-08 15:22:40
·
answer #7
·
answered by il0vechinchi 1
·
0⤊
0⤋
pi r round?
2006-07-08 18:57:41
·
answer #8
·
answered by smutz 4
·
0⤊
0⤋
± pi
2006-07-08 16:22:26
·
answer #9
·
answered by cat_lover 4
·
0⤊
0⤋
pi or negative pi
2006-07-08 17:23:16
·
answer #10
·
answered by Anonymous
·
0⤊
0⤋
pi
2006-07-08 16:27:43
·
answer #11
·
answered by The Game BOY ! 1
·
0⤊
0⤋