What is the magnitude of charge in EM waves at the zenith??

Question

I am trying to understand EM waves. These are transverse waves which as they propagate create a E/M waves. I want to know the MAGNITUDE of the charge at the maximum points. The charge is 0 to begin with. Then after ¼ cycle it reaches a +ve max. It then decreases to 0. Then goes to –ve max and again back to 0 completing 1 cycle of its frequency. My question is what the value of the charges at the zenith. Do they equal the charge of an electron? Or does the magnitude at zenith depend on the frequency of the EM wave?

Someone answered that light has E/M field without a corresponding charge. SO my question is: Hasn't the fluctuating charge associated with a wave never been measured? If it is fluctuating, this means it goes through a MAX and 0. My question stands: WHat is the magnitude of that MAX? Is it measurable and has it been measured?

Answer 1

Magnitude at zenith does not relate to frequency at all on a single case observation, but totally so when multiple provocation is looked at. Each wave is equal to itself in rotational expression at any point of observation in cycle. This includes the zenith. The magnitude at zenith remains a constant in relation to each instance of provocation. Each individual provocation produces it's own zenith magnitude, and spectral continuity.

Answer 2

There is no charge or current involved, but that doesn't mean that you can't measure the sizes of the electric and magnetic fields -- you can. That's what an antenna does.
You can measure either and get the other by Ohm's law using the impedance of empty space: 377 ohms.
If you have the usual sort of AM-FM radio, it has two antennas. The FM antenna is a metal rod that extends to about two feet long; it uses the electric field. The AM antenna is inside the case, and is a ferrite rod with a coil of wire wrapped around it; it uses the magnetic field. Typical field values for the electric field to give useful reception are a few microvolts per meter.

Answer 3

You can have electrical fields without a charge!

For an analogy, an EM wave is also magnetic, and magnetic charges don't even exist.

The precise mathematical formulation of EM phenomena involves the four Maxwell's Laws. Only the first of them refers to electrical charge (or charge density):

"the divergence of the E-field is equal to the charge density at any point in space"

So if there are no charges, the divergence of the E-field is zero -- but that does not mean that the E-field itself is zero. Conversely, the presence of an E-field does not mean that there has to be a charge.

Answer 4

you seem to be confused. There is no charge associated with the wave itself once the wave has been created. Electromagnetic waves are composed of photons. Photons have no charge. Classically, the EM wave is thought of as being a time-varying electric field which induces a changing magnetic field, which in turn induces a changing electric field....and the cycle continues.

Answer 5

The amplitude of electric intensity of the electro magnetic wave is given by {P * omega/ C^2 R}
P is the dipole moment producing em wave.
Omega = 2pi n, n is the frequency of the wave.
C the speed of the wave
R is the distance from the source.