Data is not sufficient.
A=10+B
B=20+C
These imply that A=30+C.
Required %=(30/C)*100%
To find the % more marks, we need to know the marks of C. Marks of any one of the three or any other condition to find the marks is to be included in the problem.
2006-07-07 22:57:08
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answer #1
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answered by K N Swamy 3
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A large no. of possible % as there are various assumptions for the marks each one get
If A gets 30 c gets 0 & if C get 100 A gets 130
So a lareg no. of answers are possible
2006-07-08 05:17:51
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answer #2
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answered by SHUBHU 2
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What is this, your math final?
The question would have to depend on the amount of marks that "C" gets. If "A" recieved 22000 marks, then "C" would have to have recieved 21970 which would equal out to .02% more whereas if "A" recieved 40 marks, then "C" would recieve 10 marks which would equal out to 75%. more.
2006-07-08 04:35:16
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answer #3
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answered by Bjorn 7
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how much?
just 30 marks
2006-07-08 04:36:32
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answer #4
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answered by Number-1 2
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can't answer, need to know now much marks at least one of them gets.
otherwise both A=30,B=20,C=0 and A=530,B=520,C=500 satisfy the conditions, but give different %.
2006-07-08 04:32:36
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answer #5
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answered by Anonymous
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there are 30 more marks then c but to find the % i need more info then what you have given me.
2006-07-08 12:48:47
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answer #6
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answered by akuni16 2
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30 times of basic degree of C
2006-07-08 05:48:42
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answer #7
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answered by AboAyman 5
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27.28 %
2006-07-08 06:32:44
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answer #8
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answered by star 1
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