Two objects the same size but different density (different mass) were dropped on Earth. Which encounters more air resistance?
a. the same
b. the heavier one
c. the lighter one
d. proportional to the weight of the object
e. inversely proportional to the weight of the object
f. depends on the shape of the object (pls give more details if possible)
g. depends on how much air resistance there is (pls give more details if possible)
h. Others (pls specify)
2006-07-07 18:41:04 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Physics
sry, forgot to add same size is same shape.
2006-07-07 18:49:23 · update #1
The Force of Drag can Be Approximated By the Following Equation
F = -.5*p*v^2*A*C
Where p (which should really be rho) is the density of the fluid, in this case air, v is velocity, and A is the cross-sectional area of the object. Thus, if the cross-sectional area is the same, at least by this approximation, the drag force should be the same
2006-07-07 18:49:38 · answer #1 · answered by yauwforab 2 · 1⤊ 0⤋
H.
Same size has to mean same shape, otherwise the size in another dimension is off.
When comparing the air resistence between two objects the same shape and size, surface becomes an issue (smooth/rough).
That will be the defining factor.
2006-07-08 02:04:41 · answer #2 · answered by Don't look too close! 4 · 0⤊ 0⤋
f - the larger object will face more resistance.
that is not to say that it will fall slower - the speed depends on both weight and air resistance.
2006-07-08 01:48:16 · answer #3 · answered by Anonymous · 0⤊ 0⤋
f - unless same size means same shape as well... then air resistance should be equal at the same falling speed.
2006-07-08 01:44:16 · answer #4 · answered by Chlodovocar 2 · 0⤊ 0⤋