The root of a negative number is not real. Other people above showed it.
Be careful what you say; look.
In root(3-v) the v may be 3 at the most.
In general:
Root(expression) is only real for expression is not negative.
2006-07-07 19:02:54
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answer #1
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answered by Thermo 6
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Domain is the set that has the values for which the function is defined. This is the basic definition of Domain but more precisely it is as follows
Given a function f:X→Y, the set X of input values is called the domain of f, and Y, the set of possible output values, is called the codomain. The range of f is the set of all actual outputs {f(x) : x in the domain}. Sometimes the codomain is incorrectly called the range because of a failure to distinguish between possible and actual values.
So when any number is squared it gives a positive result (i.e., the result is a positive number) and therefore contrarily the reverse also exists. So the domain of a square root function always x>=o.
2006-07-07 18:29:26
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answer #2
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answered by Sherlock Holmes 6
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Because by its nature a square root function cannot be negative.
There is a branch of Mathematics that deals with negative square roots, but they are called imaginary numbers.
2006-07-07 18:23:36
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answer #3
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answered by rhutson 4
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A + number times a + number is positive.
A - number times a - number is positive.
A - number times a + number is negative, but these are always different numbers, (-1 and 1 are completely different numbers) and the square root is asking "what number times itself equals the number underneath the funny looking square root roof?"
2006-07-07 18:39:04
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answer #4
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answered by Hume 1
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You can't have a negative square root of a real number, so the solutions (y-positions) are all positive or 0.
2006-07-07 18:24:04
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answer #5
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answered by cptbirdman 2
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until u come to the course of iota u cannot take out square root of negative number.
2006-07-07 18:30:06
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answer #6
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answered by sam_indian18 1
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b/c negative numbers do not have square roots (at least in real numbers)
2006-07-07 18:24:14
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answer #7
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answered by Anonymous
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sqrt(x^2 + 7) has no regulations on x. The area is all actual numbers. we are able to take the sq. root of any efficient volume or 0. on the grounds that x^2 is continually efficient, x^2 +7 is continually efficient and there aren't any regulations on x.
2016-11-06 01:08:44
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answer #8
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answered by ? 4
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There is no real number that is negative, and you can multiply it by itself to get a negative number.
Remember:
(-)(-) = (+) Always for real numbers.
2006-07-07 18:23:25
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answer #9
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answered by powhound 7
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If -a * -a = +A and +b * +b = +B then ? * ? = - !
2006-07-07 18:29:30
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answer #10
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answered by temptnu37076 2
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