x^2-22x+121
the answer i got was (x-11)^2 is this the same as the choice
(x-11) (x-11) or is this problem not factorable-prime????
2006-07-07 17:27:03 · 4 answers · asked by investing1987 3 in Education & Reference ➔ Homework Help
so what is the answer??? i
2006-07-07 17:34:37 · update #1
its (x-11)(x-11)! it can also be (x-11) to the second power. so both are totaly correct
2006-07-07 18:28:10 · answer #1 · answered by russian_honey007 2 · 7⤊ 1⤋
The answer is (x-11)^2, and that is the same as (x-11)(x-11).
If the polynomial was X^2-121, then the factors would be
(x-11)(x+11).
2006-07-08 00:37:47 · answer #2 · answered by krissydahs93 4 · 0⤊ 0⤋
The answer is the same. It means exactly the same thing, but to factor completely--meaning break down all the parts--you would want to take the square out ( ex: 4= 2^2 = 2x2).
2006-07-08 00:33:24 · answer #3 · answered by Jolie 3 · 0⤊ 0⤋
its actually equal to (x-11) (x+11) if i remember correctly.
2006-07-08 00:29:53 · answer #4 · answered by Rara 6 · 0⤊ 0⤋