What's the integral of xe^x?

1 ⤊

2006-07-07 13:29:14 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

Integrate by parts:

u=x
du=dx
dv=(e^x)dx
v=e^x

∫x(e^x)dx= x(e^x)-∫(e^x)dx =(e^x)(x-1)+c

2006-07-07 13:35:35 · answer #1 · answered by Eulercrosser 4 · 1⤊ 0⤋

Use parts. Let u=x and dv=e^x
The answer would be xe^x -e^x.

2006-07-07 20:37:55 · answer #2 · answered by ChemE 1 · 0⤊ 0⤋

â«e^x dx= â«(x)' * (e^x)dx = x * e^x - â«x * e^x dx = e^x

=>> â«x * e^x dx = (x - 1) e^x

2006-07-07 21:41:49 · answer #3 · answered by JinX 2 · 0⤊ 0⤋