Has anyone ever come up with a mathematical formula for solving arguments?

Answer 1

yeah it's called compromise

Answer 2

Systems of logic are the closest thing to what you're looking for.

There are various systems of mathematical logic which can be used to derive results from certain premises. "Socrates is a man; all men are mortal; therefore Socrates is mortal" is one of the more famous examples of this.

However, to apply such logical systems to a given argument, you'd have to 1) define your terms clearly; 2) agree on the premises to be used; 3) convert your premises and other statements into logical form (which logicians call "well-formed formulae"); and then 4) use the logical system to derive conclusions.

Very often, in the course of 1) and 2) above, two people having the argument will find that they have only been arguing over the meaning of words or over assumptions.

There are also algorithms (procedures) for dealing with statistical problems; look up for example Bayes' theorem.

Answer 3

Define P(n) as the probability function of a man winning a given argument, n. Let N be the total number of all concievable arguments.

The summation of P(n) from n=1 to N equals zero.

We can conclude that the probability of a woman winning a given argument is one. QED

Answer 4

I think logic tables would be the best "mathematical" approach.

When I took Discrete Math and learned how to compare two statements and look at all the probable truth/false scenarios, I started to beat all my friends at arguments, cause I was doing these "tables" in my head. Arguments were finally in aform I could better understand, MATH! And these are people who always considered themselves to be right and I could never get my point accross, suddenly I had them second guessing themselves. hehehe *smiles evily*

Answer 5

The golden ratio is the ratio of the two factors of a rectangle for which, in case you do away with a sq. from one end of it, then what's left nonetheless has factors interior an identical ratio. So from this you are able to particularly artwork out a formula for the golden ratio. If the rectangle has factors a and b then if we do away with a sq. of side a from one end of it we get a rectangle with factors b-a and a. So for b/a to be the golden ratio we choose: r = b/a = a/(b-a) = one million/(r-one million) -- divide a/(b-a) suitable and backside by way of a r(r-one million) = one million r^2 - r -one million = 0 fixing this quadratic we get r = (one million + sqrt(5))/2 or r = one million.618... (There are 2 ideas of course yet one is destructive and we are purely involved interior the beneficial result)

Answer 6

Arguing -2 no arguing= no arguing

Answer 7

2x-2y=o, assume x=y