help me solve; an even # is greater than 5 *3 and less than 7 *3, find the number if it is a square number? 16 or 18 or 20 or neither?
please help solve
2006-07-07 09:35:16 · 11 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
yes, the answer is 16, 21>16>15, 4*4=16. If I understand the question correctly.
2006-07-07 09:41:41 · answer #1 · answered by brewman007 2 · 0⤊ 1⤋
3
2006-07-07 19:31:23 · answer #2 · answered by thedude2005 3 · 0⤊ 0⤋
3
2006-07-07 16:50:39 · answer #3 · answered by Anonymous · 0⤊ 0⤋
8-x=5, then 8-5=3, then x=3.
5*3=15 and 7*3=21, the only even numbers between the two are 16,18, or 20. Of these, only 16 has a square root of 4, and is an even, whole number.
I hope this is clear to you?
2006-07-07 16:51:17 · answer #4 · answered by hillbilly 7 · 0⤊ 0⤋
x is an even no. between 15 and 21 and is also a square.
Think: The even nos. between 15 and 21 are 16, 18, and 20, but the only one of three that is a square is 16 (16 = 4 squared). So 16 is your answer.
2006-07-07 16:41:51 · answer #5 · answered by G.V. 6 · 0⤊ 0⤋
Sounds like 16. It is between 15 and 21 and 16 is a square of 4.
2006-07-07 16:56:15 · answer #6 · answered by Anonymous · 0⤊ 0⤋
it is 16 , a square of 4, i.e 5*3 < 4*4 < 7*3
2006-07-07 16:58:42 · answer #7 · answered by jara 2 · 0⤊ 0⤋
5x3=15
7x3=21
even numbers between 15 and 21 are 16,18,20.
out of these only 16 is a square number as 4x4= 16
so your answer is 16
2006-07-07 17:07:16 · answer #8 · answered by flori 4 · 0⤊ 0⤋
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2006-07-07 16:59:17 · answer #9 · answered by Anonymous · 0⤊ 0⤋
16.
4*4=16
16 is the only number out of these three which is a square number. The other two don't have a natural square root
2006-07-07 16:46:37 · answer #10 · answered by RageFalcon 1 · 0⤊ 0⤋