chemistry question?

Question

2CO+O2===>2CO2
how many gram of carbon dioxide form if 17.00 gr of carbon monoxide are combined with excess oxygen.

Answer 1

No . of moles of carbon mono-oxied burnt = 17/(12+16)=0.60 moles.

2 moles of co give 2 moles of carbon dioxide

===> 0.6 moles co will give 0.6 moles of carbon dioxide

===> 0.6*(12+(16*2))=0.6*44= 26.4 g




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Answer 2

26.71428

You just have to turn grams of CO into moles of CO and then multiply the moles of CO you have by the molar mass of CO2,

since the CO and CO2 both have the same number in front of them in the equation there is no need to adjust anything,

17/(12+16)=.60714

.60714*(12+16*2)=26.714

Answer 3

C = 12 grams/mole and O = 16 grams/mole so CO = 28 grams/mole and CO2 = 44grams/mole. There are .61 moles of CO and a molar ratio of 2:2 so there must be .61moles of CO2

.61moles * 44g/mole = 26.84 grams

Answer 4

Molar mass of CO = 12+16 = 28g

Molar mass of CO2 = 12+32 = 44g

So, 28g of CO gives 44g of CO2

Thus 17g of CO will give 44x17/28 g of CO2 = 26.71 g of CO2

Answer 5

Must use stoichiometry, or covert it all to moles...

17g of CO = 17g / 28g/mol or .607 moles of CO.

Then, 2 moles of CO reacts to form 2 moles of CO2, so ratio is 2:2 or 1:1.

If .607 moles of CO reacts then .607 moles of CO2 will be formed with excess O2.

.607 moles of CO2 = .607mol x 44g/mol (molecular mass of CO2) = 26.708g of CO2 produced

Answer 6

okay, so since moles CO=moles CO2 stoichiometrically, just convert 17 grams of CO to moles to grams of CO2.

Answer 7

K = Potassium

Answer 8

umm... say what?! i don't think that i am in that grade! i am only 13!!!!!

Answer 9

26.7142857g