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2006-07-07 05:23:17 · 12 answers · asked by kittytalker 3 in Science & Mathematics Mathematics

12 answers

take the top # and divide by the bottom

2006-07-07 05:26:49 · answer #1 · answered by islandgrl 4 · 1 0

Basically divide the numerator (number on top) by the denominator (number on bottom). Additionally, note when the numerator has "run out" (that is, consists of zeros to the right) and start looking for when the remainder of a division appears a second time. This marks the beginning of a repeated string. For example, converting 1/7 to decimal form you divide 1.00000.. by 7. The result is .142857 and then the remainder again becomes 1 so bringing down another zero forms 10 and the next answer digit will be 1 since 10/7 = 1 (with remeainder 3). so the string repeats .1428571428.. etc. ALL proper fractions (that is, whole number on top and bottom) will convert to a decimal that eventually recurs (even if the recurring string is zero, as in 1/4 = .2500000...) Note that you can often see shortcuts where the denominator consists of 9s followed by zeros. For instance, 17/90 = .18888.. and 5/9 = .555555..

2006-07-12 10:32:55 · answer #2 · answered by Anonymous · 0 0

find an equivalent fraction that has a base 10 denominator... (1/10 ... 1/100 ....etc...)

1/8 as a decimal .... 8 goes into 100, 12 1/2 times ... multiply the numerator by this factor ( 1 * 12 1/2 = 12 1/2 .... or 12.5 ... this gives you 12.5 / 100 ... now write the number in the numerator then move the decimal the number of zeros in the denominator ... write 12.5 then move the decimal piont two places to give you .125

2006-07-07 12:52:06 · answer #3 · answered by Brian D 5 · 0 0

It's pretty easy for terminating decimals, but get's tricky for repeating decimals.

Here is how you do it:


Let x=a/b (a and b are integers)
By the division algorithm a=b(s1)+(t1) where (s1) and (t1) are integers and 0≤(t1) Now we need to find the decimal part of it:
(t1)/b<1. Consider 10(t1)/b. As a, 10(t1)=b(s2)+(t2) with 0≤(t2) Thus x=(s1)+(s2)/10+(t2)/10b= (s1).(s2)+[(t2)/b]/10.
Repeat this process until the first time (ti)=(tj) for some i≠j. At this point, start repeating the (sn)'s from i+1 to j.

That is confusing, but here are some examples:

1/2.
1=0•2+1/2.
(Multiply 1 by 10) =>> 10=5•2+0 ==>> thus 1/2=0.5 +(0/2)/10
(Multiply 0 by 10)==>> 0=0•2+0 ==>> we are repeating, so 1/2=0.50000 . . . =0.5

12/7=1•7+5/7.
(multiply 5 by 10) ==>> 50=7•7+1 ==>> thus 12/7=1.7+[1/7]/10
(multiply 1 by 10)==>> 10=1•7+3 ==>> thus 12/7=1.71+(3/7)/100
" " ==>>30=4•7+2 ==>> 12/7=1.714+(2/7)/1000
" " ==>> 20=2•7+6 ==>> 12/7=1.7142 +(6/7)/10000
" " ==>> 60=8•7+4 ==>> 12/7=1.71428 +(4/7)/100000
" " ==>> 40= 5•7+5 ==>> 12/7=1.714285 +(5/7)/1000000
but (t1)=5=(t7) thus we need to repeat the (sn)'s from 2 to 7. These are 7,1,4,2,8,5. Thus 12/7=1.714285714285 . . . with 714285 repeating forever.

2006-07-07 12:32:20 · answer #4 · answered by Eulercrosser 4 · 0 0

4/5 = .80
6/5 = 1.2

Everytime you cannot divide a number put a (.) and add a 0 next to that number.

6 has one 5 in it. So put a 1 and the reminder is 1 ( 6 - 5). Now try to divide 1 by 5. 1 has zero 5 in it. So put a (.) and attach a 0 next to the reminder (1) which will be 10. Now 10 has two 5s in it. and put 2 after the (.)

This is a simple example. You can google to see better and big examples.

2006-07-07 12:35:24 · answer #5 · answered by JK 2 · 0 0

Divide the numerator by the denominator

3/4 = .75

2006-07-07 14:18:13 · answer #6 · answered by Adam A 2 · 0 0

The top number divided by the bottom number
examples 1/2 equals .50 11/12 equals .9166
To easy.

2006-07-07 12:30:19 · answer #7 · answered by The Pooh-Stick Kid 3 · 0 0

thats easy. you just divide the numirator into the dinomirator. simple turms. you divide the top into the bottem. ex 1/5 1divided by 5 = .2 or 5/1 = 5

2006-07-08 12:54:08 · answer #8 · answered by akuni16 2 · 0 0

divide the bottom by the top number;;

ex:

4/5=4 divided by 5

=.80!

2006-07-07 12:26:51 · answer #9 · answered by ▲▼▲▼ 5 · 0 0

Divide numerator by denominator.

2006-07-07 12:26:28 · answer #10 · answered by BowtiePasta 6 · 0 0

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