2006-07-07 04:33:50 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
what's the question?
2006-07-07 04:40:50 · answer #1 · answered by Scott R 6 · 0⤊ 0⤋
is that an x squared.....if so this is how you do the problem
4x^4-4x^2-5x-4x+5x-6
then from here you add and subtract like terms to get
=4x^4-8x^3-x^2+5x-6
I think thats it....
2006-07-07 11:42:41 · answer #2 · answered by poetic_lala 5 · 0⤊ 0⤋
(x^2 - x)(4x^2 - 4x - 5) - 6
4x^4 - 4x^3 - 5x^2 - 4x^3 + 4x^2 + 5x - 6
4x^4 + (-4 - 4)x^3 + (-5 + 4)x^2 + 5x - 6
4x^4 - 8x^3 - x^2 + 5x - 6
2006-07-07 11:40:35 · answer #3 · answered by Sherman81 6 · 0⤊ 0⤋
4x^4-4x^3-5x^2-4x^3+4X^2+5x-6
4x^4-8x^3-x^2+5x-6
2006-07-07 11:40:59 · answer #4 · answered by dave 2 · 0⤊ 0⤋
((x*x)-x)((1+1+1+1)((x*x)-x) -1-1-1-1-1)-1-1-1-1-1-1
2006-07-07 12:32:36 · answer #5 · answered by PØstapØc 2 · 0⤊ 0⤋