Try to answer this question, its impossible?

Question

A^3+B^3=C^3

Rules
A, B, and C cannot be negative, 1, or 0. Good luck!

Answer 1

You forgot: A, B, C cannot be decimals/irrational numbers.
so the answer is so easy.

1^3 + 2^3 = ((cube root of) 9)^3
1 + 8 = ((cube root of) 9)^3
9 = 9
So my answer is correct!


Anyway if A, B and C must be a whole number,
then don't need to scold yourself if you don't know how to solve:

Fermat's Last Theorem states that

x^n + y^n = z^n

has no non-zero integer solutions for x, y and z when n > 2.

Answer 2

A=2, B=2, C=2*(2^(1/3))


First of all you stated it wrong:

State it as A, B, and C are none zero integers!!

(it doesn't matter if they are negative or not)
Assume that it is solvable with A<0, B, C>0:

Then A^3+B^3=C^3 <==> B^3=C^3-A^3=C^3+(-A)^3

Assume A, B<0, C>0:
This is not possible Since A^3+B^3<0 and C^3>0

All other cases can be made by negating, and thus showing that it doesn't matter if they are negative or positive, it only matters if they are non-zero integers.

Answer 3

This is an example of Fermat's Last Rule. It is know that there are no solutions to:

A^N + B^N = C^N

with N an integer for N > 2 (with N = 2 Pythagoras theorem of course).

Answer 4

a=5,b=5, c=10
then A^3+B^3=C^3

Answer 5

i tried but i think its impossible coz after solving it , i was again back to a^3 + b^3 = c^3
so no use ! :-(

btw, is this actually a question (coz then only can we be sure that it has an answer) or this is a question that u hav invented??

Answer 6

If A, B, C are integers there is no solution. But, there are several solutions if A, B, C (atleast any one) are real.

Answer 7

The answer is to go on to another question

Answer 8

the answer is:

chicken soup

Answer 9

this is impossible
i tried so hard, but i couldn't do it
sorry

Answer 10

I failed math......twice =)