a bomb is dropped from an airplane 1500m above the ground when the plane is moving horizontally at the rate of

Question

at the rate of 160 km/h.where should the plane be with respect to the target when the bomb is dropped if a hit is to be made?

Answer 1

DOWN RANGE

Answer 2

Since the bomb and plane are both moving at a horizontal rate of 160 km/h (neglecting air resistance) they will be the same horizontal distance from the target. If you mean "how far away is the target from the drop point?" then the plane needs to release the bomb around 780 m before the plane is directly over the target (or about 17.5 s before it is over the target) in order for the bomb to land directly on the target.

Answer 3

i will provide you a huge hint. First u say that that's 1500m above the floor, so u understand its height and would certainly calculate the time taken to achieve the floor (use s=ut+a million/2at^2 take u=0 a=+g) 1500=a million/2*10*t^2 (u can take g=9.8 if u favor) t=sq.(three hundred) now, u have t seconds for the bomb to achieve the objective accl interior the horizontal direction is 0 take initial velocity to u= 15kph=seventy 5/18m/s=25/6m/s subsequently employing an same formula back s=u*t+a million/2at^2 u get s=u*t s=25/6*sq.(three hundred) that is the ans.

Answer 4

if the plane contiues on course at the same rate...and there were no wind resistance acting on the bomb or the plane....then when the bomb hits the ground the plane should be directly 1500M above it

Answer 5

Strike vertical velocity of bomb=sqrt(2*9.8*1500)=171.5 m/s
Plane velocity=44.4 m/s=160 km/hr
Time elapsed by bomb to hit target= 171.5/9.8=17.5 seconds
To hit the target the horizontal distance of the plane should therefore be 44.4m/s*17.5s=777m.