2006-07-05 18:49:28 · 5 answers · asked by albosweetthing 1 in Science & Mathematics ➔ Mathematics
(3/5) (x^3-14x^2+3x-15)^(-2/5) (3x^2-28x+3)
2006-07-05 18:55:30 · answer #1 · answered by buxinator 3 · 0⤊ 0⤋
given y=((x^3-14x^2+3x-15)^3)^5/2
since the fifth root is 5/2
this becomes y=(x^3-14x^2+3x-15)^15/2
since roots are multiplied
now differentiating
dy/dx=15/2 * [(x^3-14x^2+3x-15)^ (13/2)]*(3x^2-14*2*x+3)
since 15/2-1=13/2
now dy/dx=15/2*[(x^3-14x^2+3x-15)^(13/2)]*3x^2-28x+3)
2006-07-06 02:26:50 · answer #2 · answered by priya 2 · 0⤊ 0⤋
y'= 3/5(x^3-14x^2+3x-15)^2 * (3x^2-28x+3)
you can prolly simplify this..
2006-07-12 12:35:11 · answer #3 · answered by schleppin 3 · 0⤊ 0⤋
This is from my mathematics nightmare...
2006-07-06 01:52:30 · answer #4 · answered by ooh_rah07 4 · 0⤊ 0⤋
oh my god....
i wanna puke only when i see it....
thank god i dont need it any more!!!!!
(sorry,i dont have a clue whats the answer)...
2006-07-06 01:53:18 · answer #5 · answered by me me 2 · 0⤊ 0⤋