Please help with this quadriatic formula!!?

Question

I am confused with this problem which is 8x^2 + 1 = 5x. Is the answer -5 - i square root 7/16, -5 + i square root 7/16?

Answer 1

now take everything to the left side
8x^2-5x+1=0
the formula is [-b(+ or -)sqr root of (b^2-4ac)]/2a
where a=co.factor of x^2
b is the co.factor of x
& c is the constant
here a=8, b=-5 & c=1
then substituting in the formula
[5(+ or -)sqr root of (25 - 4*8*1)]/2*8
=[5(+ or -) sqr root of (25-32)]/16
=[5(+ or -) sqr root of (-7)]/16
=(5(+ or -) i * sqr root of 7)/16
so the answer is
5 (+ or -) i*sqr root of 7/16

Answer 2

8x^2 + 1 = 5x
8x^2 - 5x +1 = 0
by quadratic formula,
x = (-5+7i)/16 or (-5-7i)/16
as i^2 = -1 or i = square root of -1

Answer 3

I believe the answer i gave previously was

x = (5 - isqrt(7))/16 or (5 + isqrt(7))/16

If you don't believe me, go check out www.quickmath.com, click on Solve under Equations, then type in 8x^2 + 1 = 5x

it will give you the same as as the one i gave you.

Answer 4

x12= -b +- (b^2-4ac) where a=8 b = -5 c=1 - the coefficents of the powers of x

so the roots are 5+7i and 5-7i and their sum equals b/a=10

Answer 5

sorry ur answer is wrong as the sum of ur roots is not equal to -b/a in ur equation which should be -10 and not -5/8

Answer 6

I won't give you the answer but I will help by saying it is sinply a ratio of the magnitude of x : unity.