jons age is 5 more than twice bills age . the sum of the all of the ages is 50. find both of their ages?

Answer 1

Bill - 15
Jon - 35

Answer 2

jons = 5 + (2 x bills)

sum = jons + bills
50 = 5 + (2 x bills) + bills
50 = 5 + 3bills
3bills = 45

bills = 15

sum = jons + bills
jons = 50 - 15

jons = 35

Answer 3

Let Jon's Age = j
Let Bill's Age = b

We write "Jon's age is 5 more than twice Bill's age"
eq#1: j = 2b + 5,
and "The sum of all of the ages is 50"
eq#2: j + b = 50.

Solving eq#2 for b we get
b = 50 - j

Substituting the above value of b into eq#1 we get
j = 5 + 2(50 - j).

The arithmetic to solve for j is broken down as follows.
j = 5 + 2*50 - 2j
j = 5 + 100 - 2j
j + 2j = 105
3j = 105
j = 105/3
j = 35

Now we put the above value for j into eq#2 which gives
b = 50 - 35
b = 15.

Since j = 35 and b = 15 we conclude that Jon's age is 35 and Bill's age is 15.

Answer 4

This is one of those questions that you need to work backwards to get the answer. So, you start with 50, Jon is 5 more than TWICE, which is multiplication, but since you are working backwards, you must divide, in this case, by 2. So now you have 25. Next Jon is 5 MORE, which would be addition, so we must subtract, which gives you 20. To check the work, Jon must be 20, which is 5 more than twice bills age, then bill must be 15x2, which is 30. 30 +20 =50, and there is you answer!

Answer 5

Bill is 15. Jon is 35

Answer 6

2x+5+x=50
3x+5=50
3x+5-5=50-5
3x=45
3x/3=45/3
x=15


x is bills age since you have 2*bills age +5 + his own age
15*2+5=35

Jon-35
Bill-15

check ya later ♥

Answer 7

Jon is 35
Bill is 15

Answer 8

J = 2B + 5

J + B = 50
(2B + 5) + B = 50
2B + 5 + B = 50
3B + 5 = 50
3B = 45
B = 15

J = 2B + 5
J = 2(15) + 5
J = 30 + 5
J = 35

Jon's age is 35
Bill's age is 15

Answer 9

Bill = 15
Jon = 35

Answer 10

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