D -333i
2006-07-05 15:11:18
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answer #1
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answered by yates8806 1
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The answer is D and that is because when you FOIL the question you get "54-9i-324i+54i^2" which goes to "54-333i+54i^2) and the 54 cancels which leave -333i
2006-07-05 15:14:45
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answer #2
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answered by kvm1947 2
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D)
54 - 9i - (54*6)i + 54(i^2)
54 - 333i - 54
333i
2006-07-05 15:11:43
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answer #3
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answered by something 3
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(9-54i)(6-i)
Following the FOIL method you should have gotten
54 -9i - 324i +54i^2
54 -333i +54(-1)
= -333i
which is answer Option D.
Guess you just missed out on the -324i ??
2006-07-05 15:12:50
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answer #4
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answered by Math Help 2
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The answer is -333i
(9-54i)(6-i)=54-9i-324i+54i^2
=-9i-324i
=-333i
2006-07-05 15:14:53
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answer #5
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answered by zmonte 3
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(9 - 54i)(6 - i)
54 - 9i - 324i + 54i^2
54 - 333i + 54(-1)
54 - 333i - 54
-333i
ANS : D.) -333i
i^2 = (sqrt(-1))^2
the sqrt and ^2 cancel out
i^2 = -1
2006-07-05 17:04:44
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answer #6
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answered by Sherman81 6
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Your 54 and -54i^2 parts are correct, but you didn't multiply the 6*-54i and the 9*-i parts. first (9*6), inner (-54i * 6), outer (9*-i), last (-54i * -i). Multiply all those and add them together. Got it?
2006-07-05 15:15:55
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answer #7
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answered by mkerley 2
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remember FOIL (multiply first terms, then outiside, then inside, then last)
54 -304i-9i+54i^2
-333i
2006-07-05 15:16:14
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answer #8
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answered by enginerd 6
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(a + bi) (c + di) = (ac - bd) + (ad + bc)i
(9 - 54i) (6 - i) = (54 - 54) + (-9 - 324)i
= 0 + (-333)i
= 0 - 333i
2006-07-05 15:15:11
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answer #9
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answered by Danny B 3
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9 * 6 = 54
-54i * -i = -54
9 * - i = -9i
6 * -54i = -324i
= - 333i
2006-07-05 15:13:09
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answer #10
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answered by Poncho Rio 4
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complicated volume aspects calculate the picture of ordinary numbers, you in ordinary words ought to recollect that i² = -a million. (24 - 4i)(6 + i) = 24 * 6 - 4i * 6 + 24 * i - 4i * i = one hundred forty four - 24i + 24i - 4i² = one hundred forty four - 4i² = one hundred forty four - 4(-a million) = one hundred forty four + 4 = 148
2016-11-01 06:46:54
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answer #11
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answered by Anonymous
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