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how much time id required for the box to reach the earth?how far does it travel horizontally while falling?find the horizontal and vertical components of its velocity when it strikes the ground?

2006-07-05 14:31:01 · 7 answers · asked by Anonymous in Science & Mathematics Physics

7 answers

Issue One:
Assuming that the box is completely devoid of friction with the air, you would use the equation x(f) = x(i) + 0.5*a*t^2 or "final position is equal to the initial position + 0.5 times the acceleration times the time of the drop squared" Acelleration due to gravity is 9.8 meters per second squared

0 = -200 + 0.5*(9.8)*t^2
200 = 0.5*(9.8)*t^2
400 = (9.8)*t^2
40.8 = t^2
6.38 seconds = t
This is true rather the plane and box were initially standing still or moving at 300,000 meters per second

Issue Two:
Assuming (again) no air resistance, the box will be traveling at the same rate as the plane after being released so in the 6.38 seconds travels in the horizontal plane it will travel 100 meters for every one of the 6.38 second it travels or 638 meters

Issue Three:
We already know that the box is still traveling 100 m/s horizontally so the only missing part is the vertical velocity. This is solved using the formula v(f) = v(i) + at

v(f) = 0 [since it was dropped without force] + (9.8 m/s)(6.38)
v(f) = 62.5 m/s

2006-07-05 15:03:56 · answer #1 · answered by Science Teacher 2 · 0 0

Height, H = ½ g t^2.

t ^2 = 2H/g = 2 x200 /9.8 = 40.82

Time to reach the ground t = 6.38(876560) s = 6.4 s.

The distance traveled horizontally is the horizontal velocity x time of fall.

S = 100 x 6.38(87656) = 639 m .

The vertical ( component) final velocity is V = gt = 9.8 x 6.38(876560) = 62.60 m/s

Or from V ^2 = 2 g H = 3920 ; V = 62.6 m/s.

The horizontal component is the horizontal speed = 100 m/s.

2006-07-05 15:05:11 · answer #2 · answered by Pearlsawme 7 · 0 0

that depends on the mass of the box.

Potential Energy= mass*velocity*gravitational pull* cos 0

cos 0 is zero because its on a flat plane.

I think the answer would be 2 seconds- because you said its 100meters per second and its at an elevation on 200m so it would only take 2 seconds.

2006-07-05 14:42:18 · answer #3 · answered by mormonjewmacabee 2 · 0 0

What is the coefficient of friction of the air?

What size is the box? Is it same size in each direction (cube)?

Do we assume it is tumbling or stationary as it falls?

2006-07-05 14:41:25 · answer #4 · answered by Poncho Rio 4 · 0 0

i've got laughed at why the fly on the wall is being so nosy. What the fly on the wal thinks of what I do,whilst the fly makes it fairly is existence by way of mountaineering on excrement and feeding on that's laughable in assessment.

2016-12-14 04:42:22 · answer #5 · answered by baron 4 · 0 0

2sec .... speed = distance / time
time= distance / speed
time= 200 / 100

2006-07-05 14:49:50 · answer #6 · answered by pepi 1 · 0 0

a couple miles, and it's gonna kill somebody that it lands on

2006-07-05 14:47:11 · answer #7 · answered by Anonymous · 0 0

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