If 2 cars leave from the same location?

Question

If 2 cars facing opposite directions leave from the same point and travel 6 miles then both make a left and travel 12 miles How many miles apart are they at their stopping point?

Answer 1

You need to use the pythagorean theorem, because if you draw a diagram of what's going on, the two cars paths' form two right triangles.
6^2 + 12^2
36 + 144 = 180
sqrt 180 = 13.41

since there are two triangles, you will need to double that. So, the two cars are approximately 26.82 miles apart.

Answer 2

They are about 26.83 miles apart.
If we say the distance from the start point of one of the cars to its end point equals X, and using some geometry on the right triangle formed...
(6^2) + (12^2) = X^2
√180 = X
Since its two cars moving in opposite directions, the total distance is twice X, or 26.83mi.

Answer 3

Assuming the drivers of each car actually followed the directions correctly, and didn't wind up stopping at a pub or bike shop along the way, they should be 26.83 miles apart. But what are the odds of that?

Answer 4

12^2 +24^2 = sqrt C
144 + 576 = sqrt C
720 = sqrt C
26.8 = C

approx. 26.8 miles apart

Answer 5

Yep. The 26.8 answers are correct. 6^2 + 12^2 = 180.

Sq root = 13.416. x 2 = 26.8 miles.

Answer 6

12 miles......is that miles traveled from each other or miles between each other. If its miles traveled its 36.

Answer 7

18 miles apart.

Answer 8

26.84 miles. What you're doing is drawing two legs of a triangle. So, a2 + b2 = c2. 36 + 144 = square root of 180 or 13.42 x 2 (for 2 cars and two triangles), or 26.84.

Answer 9

approx. 27 miles

Answer 10

26.83281573 mi. you use pathagoras theory or whatever which is a squared + b squared = c squared.